How to compare rows in a matrix

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Sameer
Sameer 2014-7-18
评论： Sameer 2014-7-18
Hello all
I have a matrix A
A =
1 1 0 0 0
0 -1 0 1 0
-1 0 1 1 0
lets say I am looking at the second row in which column 2 and 4 have value present now if I compare it with the row above which has values in the column 1 and column 2 so I want to know the column number which has values in both the rows, I mean here the column number 2 should be returned. Similarly row 3 should be compared with row 1 and 2 and for each row a column number should be returned.
Can anyone please guide me through this.
Regards

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采纳的回答

Azzi Abdelmalek
Azzi Abdelmalek 2014-7-18
Comparison between row 1 and row 2
A =[ 1 1 0 0 0
0 -1 0 1 0
-1 0 1 1 0]
idx=find(all(A(1:2,:)))
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Azzi Abdelmalek
Azzi Abdelmalek 2014-7-18
A =[ 1 1 0 0 0
0 -1 0 1 0
-1 0 1 1 0]
jj=0;
for k=2:size(A,1)
for p=1:k-1
B=A([p,k],:)
jj=jj+1;
out{jj,2}=find(all(B))
out{jj,1}=sprintf('(%d,%d)',k,p)
end
end

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the cyclist
the cyclist 2014-7-18
I think that
[rows,cols] = find(A(2:end,:)~=0 & A(1:end-1,:)~=0)
does what you want.
rows will be the index to the "top" row being compared, and "cols" will be the column numbers that meet your criterion.
For example, in your case
rows = [1; 2];
and
cols = [2; 4];
cols seems to be the main thing you are going for.

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