Index in position 2 exceeds array bounds (must not exceed 1) ?

Question

Prabhu R 2021-9-6

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1447609-index-in-position-2-exceeds-array-bounds-must-not-exceed-1

评论： Prabhu R 2021-9-7

My Code is :

function Hout = Hcomb(a , b , c)
%%%%% Get the size of Image 
[r ,c] = size(a);
for i = 1:r
    for j= 1:c
        if (a(i,j) > b(i,j)) && (a(i,j) > c(i,j))
            
          Hout(i,j) = a(i,j);
          
        elseif (b(i,j) > a(i,j)) && (b(i,j) > c(i,j))
                
          Hout(i,j) = b(i,j);
          
        elseif (c(i,j) > a(i,j)) && (c(i,j) > b(i,j))
            
          Hout(i,j) = c(i,j);
          
        end
    end
end    
 
  	  	
return;

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Prabhu R 2021-9-6

Error at elseif (c(i,j) > a(i,j)) && (c(i,j) > b(i,j))

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Answer 1

Simon Chan 2021-9-6

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https://ww2.mathworks.cn/matlabcentral/answers/1447609-index-in-position-2-exceeds-array-bounds-must-not-exceed-1#answer_781744

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One of the input argument is variable 'c' and you use the same name again for the size of variable 'a' and hence gives you an error, try rename them as follows:

function Hout = Hcomb(a , b , c)
%%%%% Get the size of Image 
[row ,col] = size(a);
for i = 1:row
    for j= 1:col
        if (a(i,j) > b(i,j)) && (a(i,j) > c(i,j))
            
          Hout(i,j) = a(i,j);
          
        elseif (b(i,j) > a(i,j)) && (b(i,j) > c(i,j))
                
          Hout(i,j) = b(i,j);
          
        elseif (c(i,j) > a(i,j)) && (c(i,j) > b(i,j))
            
          Hout(i,j) = c(i,j);
          
        end
    end
end    
 
  	  	
return;

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Prabhu R 2021-9-7

works good i forget about variable name

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Answer 2

DGM 2021-9-6

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https://ww2.mathworks.cn/matlabcentral/answers/1447609-index-in-position-2-exceeds-array-bounds-must-not-exceed-1#answer_781739

编辑：DGM 2021-9-6

Nothing in this code guarantees that the size of b and c are identical to the size of a. If they aren't the same size, you will end up with errors. Since you didn't reveal anything about what you passed, I'm going to have to assume that's what you did.