In this code I have a result but I want it as integer numbers.
1 次查看(过去 30 天)
显示 更早的评论
n = 12;
m = 6;
numbers = linspace(1, n, m)
index = 1;
theSums = [];
for k = 1 : length(numbers)
for k2 = 1 : length(numbers)
num1(index) = numbers(k);
num2(index) = numbers(k2);
theSums(index) = num1(index) + num2(index);
fprintf('%.4f + %.4f = %.4f\n', num1(index), num2(index), theSums(index));
index = index + 1;
end
end
[uniqueSums, indexes] = unique(theSums)
% Extract only the unique numbers:
num1 = num1(indexes)
num2 = num2(indexes)
% Double check.
for k = 1 : length(indexes)
fprintf('%.4f + %.4f = %.4f\n', num1(k), num2(k), uniqueSums(k));
end
0 个评论
回答(1 个)
Image Analyst
2021-9-26
round() will turn floating point numbers (doubles) with fractions into floating point numbers (doubles) with no fraction (the fraction is 0).
Or you can use int32() to cast your variable into a 32 bit integer, which of course also does the rounding.
0 个评论
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Operators and Elementary Operations 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!