Trying to compress a signal.

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Rafael Ortiz
Rafael Ortiz 2021-9-26
评论： Rafael Ortiz 2021-9-27
Hi guys im trying to compress a signal
n is the time vector given by : n=[0 1 2 3 4 5 6 ] and xn is the vector with the values of the discrete sequence and is: xn=[0 1 2 3 4 1 0]
signal compression is "x(2*n)", x2n= [0 2 2 0 0 0 0] .
Is there any way to calculate these new points in matlab?
Thanks!

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采纳的回答

Walter Roberson
Walter Roberson 2021-9-27
compressed_x = x(1:2:end);
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Walter Roberson
Walter Roberson 2021-9-27
Ran in:
n=[0 1 2 3 2 1 0]
n = 1×7
0 1 2 3 2 1 0
x = [0 1 2 3 4 1 0]
x = 1×7
0 1 2 3 4 1 0
n2idx = @(n) n+1;
xn = @(n) x(n2idx(n))
xn = function_handle with value:
@(n)x(n2idx(n))
x2n = @(n) x(n2idx(2*n));
xn(n)
ans = 1×7
0 1 2 3 2 1 0
x2n(n)
ans = 1×7
0 2 4 0 4 2 0

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更多回答（1 个）

Sulaymon Eshkabilov
Have you read this help DOC: https://www.mathworks.com/help/signal/ug/dct-for-speech-signal-compression.html
that explains all steps of signal compression in a logical order.

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