computational time nested if commands

2014 9 9
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更新时间：2014 9 10
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Hi there,
I am attaching an mfile with nested ifs - it is really simple and I include the commenting, so it is easily read.
However, it takes for ever to execute. The weird thing is that if I exclude only one condition (one nested if - the >1.11 Z see code) , it executes really fast. I really cannot spot weather there is a mistake in the code - it doens't return anth as an error, just simply never stops, so I was just hoping for you MATLAB guru's.
Thanx a lot in advance! Stella

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Andrei Bobrov
Andrei Bobrov 2014-9-9
编辑：Andrei Bobrov 2014-9-10

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us1 = abs(Us(:,1:48));
x = us1(:,[1:30,36:48]);
z = us1(:,[31,32,34,35]);
p = us1(:,33);
l1 = all([bsxfun(@gt,p,2*x),2), bsxfun(@gt,p,1.11*z)],2);
Usvalid = Us(l1,:);
Usnonvalid = Us(~l1,:);

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Stelina
Stelina 2014-9-9
Andrei thanx for the answer. If I understand correctly, the code is equivalent with (i was getting error):
us1 = abs(Us(:,1:48));
x = us1(:,[1:30,36:48]);
z = us1(:,[31,32,35,36]);
peak = us1(:,33);
criterion1=bsxfun(@gt,peak,2*x)
criterion2=bsxfun(@gt,peak,1.11*z)
l1 = all([criterion1, criterion2],2);
Usvalid = Us(l1,:);
I get correct results. However, since criterion1 and criterion2 are my new arrays as returned by bsxfun, how does the all command above work?
And, still, do you perhaps have any idea what was going wrong with the first code with the nested ifs?
Thanx, Stella
Andrei Bobrov
Andrei Bobrov 2014-9-10
编辑：Andrei Bobrov 2014-9-10
variant with loop for..end and condition if..else..end:
us1 = abs(Us(:,1:48));
x = us1(:,[1:30,36:48]);
z = us1(:,[31,32,35,36]);
peak = us1(:,33);
k = 0;
m = 0;
for ii = 1:size(Us,1)
if all(peak(ii) > 2*x(ii,:)) && all(peak(ii) > 1.11*z(ii,:))
k = k + 1;
Usvalid(k,:) = Us(ii,:);
else
m = m + 1;
Usnonvalid(m,:) = Us(ii,:);
end
end

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