calling seperate members of a vector function

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João Teixeira 2021-10-25

评论： Matt J 2021-10-28

I want to call seperate members of my defined vector function and I don't know how to do it.

For example I defined the vector function as shown:

F=@(x,y,z) [x- y, y^2 , z+2] which shows:

@(x, y, z) [x - y, y ^ 2, z + 2]

how do i call only one member, like the first one "x-y"? Because if I do F(1) I'm defining x as equal to 1.

Ive J 2021-10-25

Why not this?

F = @(x) [x(1) - x(2), x(2)^2 , x(3) + 2];
res = F(1:3);
res(1)
ans = -1

Matt J 2021-10-26

编辑：Matt J 2021-10-26

There's no way to do that. You could do it if the components are held in struct form, e .g.,

F=@(x,y) struct('a',x-y,'b', y^2);
F(5,3).a
ans = 2

João Teixeira 2021-10-28

Ok, thanks for your help!

Matt J 2021-10-28

You're welcome, but if you consider your question answered, please Accept-click the answer.

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