0 个投票

while ((ch1(1,1)~=60)&(ch1(1,2)~=40)) ||
((ch2(1,1)~=60)&(ch2(1,2)~=40)) ||
((ch3(1,1)~=60)&(ch3(1,2)~=40)) ||
((ch4(1,1)~=60)&(ch4(1,2)~=40)))
body
end
hi,
i want to run a loop until any one of the condition ch1(60,40),ch2(60,40),ch3(60,40),ch4(60,40) met. is above syntax is correct or not. i run the above line but didn't get proper response which is desired.
kindly help me. i will be highly thankful to you :) thanks in advance

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Mudasir Ahmed
Mudasir Ahmed 2014-10-5
编辑：Image Analyst 2014-10-5
while ( (ch1(1,1)~=60)&(ch1(1,2)~=40) ) || ( (ch2(1,1)~=60)&(ch2(1,2)~=40) ) || ( (ch3(1,1)~=60)&(ch3(1,2)~=40) ) || ( (ch4(1,1)~=60)&(ch4(1,2)~=40) ) )
Jan
Jan 2014-10-5
编辑：Image Analyst 2014-10-5
I've formatted the code (use the "{} Code" button). Then it gets obvious, that there is one extra closing parenthesis.
I cannot guess what "the condition ch1(60,40)" means. So all we see is the code but we do not know, what you expect it to do. This is not enought to suggest changes.
Geoff Hayes
Geoff Hayes 2014-10-6
Mudasir - from your previous question at ga & target tracking, the (60,40) is the position of the target, the ch1, ch2, ch3, and ch4 are presumably the chromosomes of your population (of only size four?). And each chromosome has two genes (or variables). Are you trying to force a genetic algorithm to run until one of the chromosomes has converged on the target position? That won't necessarily (or even probably) happen given the small population size and the fact that the solutions may all converge prematurely to another location.
Mudasir Ahmed
Mudasir Ahmed 2014-10-6
thanks sir,
sir i have written a complete code and also it is working fine with for loop(iterations>50). now i want to make it conditional means whenever any one of the chromosome reach at target stop the loop. i have tried but failed to do this. sir kindly give me your personal email id or any other plate form on which i can discuss in detail with you and send you a complete code or even i can paste code here but it is bit long comprise of 200+ lines, i think only few changes are required and for that i need you guidance sir. thanks in advance

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 采纳的回答

Geoff Hayes
Geoff Hayes 2014-10-6

0 个投票

Mudasir - you can try the following if you want to break out of the loop if any of your chromosomes obtain a certain value (or get close enough to it). It doesn't limit you to four chromosomes (which is much too small of a population size for a genetic algorithm)
numChromosomes = 42;
chromosomes = zeros(numChromosomes,2);
tol = 0.0001;
while all(sqrt((chromosomes(:,1)-60).^2 + (chromosomes(:,2)-40).^2)>tol)
% do stuff
end
The above creates an mx2 matrix of chromosomes which will (presumably) be updated by the algorithm. The condition in the while loop uses the usual distance function
all(sqrt((chromosomes(:,1)-60).^2 + (chromosomes(:,2)-40).^2)>tol)
We compute the distance for each chromosome from the target position of (60,40). We then compare each to a tolerance tol which is a small number. If all of these distances are greater than tol then we keep iterating. If at least one is less than or equal to tol, then the condition is broken and we exit the while loop.
You do have to be careful as you may become stuck in an infinite loop as your GA population (the chromosomes) may converge prematurely to another solution (position) and so will never achieve the target position (despite the mutation or any other method you invoke against your chromosomes).

更多回答（2 个）

per isakson
per isakson 2014-10-6

0 个投票

See Continue Long Statements on Multiple Lines
while ((ch1(1,1)~=60)&&(ch1(1,2)~=40)) || ...
((ch2(1,1)~=60)&&(ch2(1,2)~=40)) || ...
((ch3(1,1)~=60)&&(ch3(1,2)~=40)) || ...
((ch4(1,1)~=60)&&(ch4(1,2)~=40))
body
end
Mudasir Ahmed
Mudasir Ahmed 2014-10-6

0 个投票

target=[60,40] % target location
ch1=[0,100] ch2=[15,85] ch3=[85,05] ch4=[95,15]
thanks sir, it is working, but iterations varies for every trial, means in first attempt good solution comes in 300 iteration after that it varies from 72,641,260....means for every trial, number of require iterations varies(require large number of iterations compare to PSO). i think it will be counter by tacking more chromosome instead of using 4. is there are another techniques to improve response other then increasing number of chromosome.
My 2nd question is that sir, robot is placed at random position e.g robot1=[10,20] and their task is to reach at target, but we have to move robot to the target in step by step manner. but as we take 4 chromosome, so how we can assign a location to robot for every iteration. (i think in every iteration value of best chromosome will be transferred to robot.)
sir my 3rd question is , as GA is not suitable or provide desired response compare to other optimization technique like PSO then what is the advantage of using it.
thanks in advance sir :)

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Geoff Hayes
Geoff Hayes 2014-10-6
Mudasir - as your answer isn't an answer to your original question (but three new questions!) then you should delete this answer and start a new thread, or continue the conversation at a previous post of yours, GAs and target tracking, so that readers of this thread do not become confused.

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