Generating a 6 second sine wave?
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I'm supposed to generate a 6 seconds long sine wave that has amplitude of 1.0, frequency of 400Hz at a 8KHz sampling frequency, but I'm not sure how to control how long the wave lasts for.
采纳的回答
Azzi Abdelmalek
2014-10-7
f=400
Amp=1
ts=1/8000;
T=6
t=0:ts:T;
y=sin(2*pi*f*t);
plot(t,y)
3 个评论
Kay Wonderley
2018-3-26
编辑：Image Analyst
2018-3-26
Hi I have done this (below).
How do I turn it into a function?
f=100;
Amp=10;
fs = 44100;
ts=1/44100;
T=10;
t=0:ts:T;
y=sin(2*pi*f*t);
sound(y,fs)
Image Analyst
2018-3-26
Add a function line:
function [t, y] = PlaySound()
f=100;
Amp=10;
fs = 44100;
ts=1/44100;
T=10;
t=0:ts:T;
y=sin(2*pi*f*t);
sound(y,fs)
Mohamad
2019-4-4
f=400
Amp=1
ts=1/8000;
T=6
t=0:ts:T-ts; % I modified this line to make signal duration 6 seconds
y=sin(2*pi*f*t);
plot(t,y)
更多回答（1 个）
Image Analyst
2014-10-7
Hint: 6 seconds at 8000 times per second means that the vector (row array) will be 48000 elements long.
sineWave = sin(2*pi*freq*timeVector);
See if that's enough hints.
3 个评论
Image Analyst
2014-10-8
Well it looks like Azzi did it all for you. Though if you ever want to change the amplitude you should use
y = Amp * sin(2*pi*f*t);
Dick Rusell
2014-10-10
Akpabio Ekpewoh
2019-7-11
Yes, just use the icons on the top of the plot
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