Help: Error using integral (line 85) A and B must be floating point scalars

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Adam
Adam 2014-10-8
评论： Geoff Hayes 2014-10-8
Hey, I am new to Matlab and I am trying to code a graph of the function listed below:
>> x = 10:0.05:20; >> func1 = @(x) 1/sqrt(2*pi)*exp(-x^2/2)
func1 =
@(x)1/sqrt(2*pi)*exp(-x^2/2)
>> func2 = @(x) (13.5-x)*sqrt(30)*(1/5)
func2 =
@(x)(13.5-x)*sqrt(30)*(1/5)
>> y = integral(func1, -9999, func2)
I keep getting this error:
Error using integral (line 85) A and B must be floating point scalars.
Can someone help me fix this error or find a way to circumvent it? Thank you.
  1 个评论
Geoff Hayes
Geoff Hayes 2014-10-8
Adam - if you put a breakpoint at line 85 of integral.m, you will understand the error. A and B are the endpoints for your integral and must be floating point scalars. In your case, A is -9999 which is fine, but B is a function handle, func2.
What is your intent of using func2 as an endpoint? If you were to write out your integral (on paper) what would it look like?

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