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function to increase the range of inverse sine

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rick
rick 2011-9-14
编辑： Walter Roberson 2018-10-26
The asin() function only returns values between (-pi/2, pi/2). How can I write a function to give me values between (0, 2pi)?

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回答（3 个）

Walter Roberson
Walter Roberson 2011-9-14
  1 个评论
Jan
Jan 2011-9-14
This will solve the problem by using the MATLAB 2013a or later. Not very efficient...

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the cyclist
the cyclist 2011-9-14
You can force the output to be within the range (0,2pi) by applying the mod() function:
>> mod(asin(x),2*pi)
Given only one input argument, you can't infer precisely which quadrant to return. Walter's answer points to a list of requested features (specifically, more two-argument versions of inverse trig functions).
theodore panagos
theodore panagos 2018-10-26
编辑：Walter Roberson 2018-10-26
You can have the asin(x,y) from 0 to 2*pi by the formula:
asin(x,y)=pi-pi/2*(1+sgn(x))*(1-sgn(y^2))-pi/4*(2+sgn(x))*sgn(y) -sgn(x*y)*asin((abs(x)-abs(y))/sqrt(2*x^2+2*y^2))
there is x=x2-x1 and y=y2-y1

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