How to compare the index values in the different matrices

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Utku Ceylan 2021-11-9

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https://ww2.mathworks.cn/matlabcentral/answers/1582669-how-to-compare-the-index-values-in-the-different-matrices

评论： Adam Danz 2021-11-11

采纳的回答： Adam Danz

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Hello,

I am trying to solve the problem 23 in Introduction to Matlab. The question asks to find the perfect squares as shown below. You can see that both 2 and 2^2 are in the same matrix.

Input a = [2 3 4]
Output b is true

I want to compare the input matrix with the root squared one but I do not know how to compare . Here is my code but it does not work. Is there any function for doing that?

a = [2 3 4]
b = sqrt(a)
if a == b
    disp('b is true')
else
    disp('b is false')
end

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采纳的回答

Adam Danz 2021-11-9

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1582669-how-to-compare-the-index-values-in-the-different-matrices#answer_827604

编辑：Adam Danz 2021-11-9

在 MATLAB Online 中打开

See isequal.

or ismember

Demo:

a = [2 3 4]
a = 1×3
     2     3     4
b = sqrt(a)
b = 1×3
    1.4142    1.7321    2.0000
ismember(a,b)
ans = 1×3 logical array
   1   0   0

To understand why your conditional statement does not work, consider this example below.

if [true false false]
    disp('TRUE')
else
    disp('FALSE')
end
FALSE
if [true true true]
    disp('TRUE')
else
    disp('FALSE')
end
TRUE

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Utku Ceylan 2021-11-10

编辑：Utku Ceylan 2021-11-10

在 MATLAB Online 中打开

Thanks a lot. I changed my code which can be seen below. However, I could not pass almost all the tests although I got the desired result. I still do not get what is wrong with my code.

a = [2 3 4]
b = sqrt(a)
 
if any(ismember(b,a)) == 1
     disp('b is true')
 else
     disp('b is false')
end

Let me copy and paste the question without changing. The question is in the "Introduction to MATLAB" problem group. The question says that:

Adam Danz 2021-11-11

I don't know what tests are performed but the code you shared produces the correct results. However, there is no need for the "==1" in your any() comment.

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