why in this function they use empty square brackets?
显示 更早的评论
and how exactly this is solving the determinant, I don't completley understand what they did here/
sorry if it's a dumb question I'm new to coding and to matlab.
function det = myDet(A)
if isscalar(A)
det = A;
return
end
det = 0;
top_row = A(1,:);
A(1,:) = [];
for i = 1:size(A,2) % number of columns
A_i = A;
A_i(:,i) = [];
det = det+(-1)^(i+1)*top_row(i)*myDet(A_i);
end
end
采纳的回答
It is not a dumb question at all, because the syntax used by MATLAB to delete a row or column of an array may not be obvious. But the best way, as others have said, is to try it out. See what happens to the array when you do that. Getting your hands dirty is the best way to learn.
A = magic(3)
% first, I'll delete the second row of A
A(2,:) = []
% Next, delete the third column of that matrix.
A(:,3) = []
更多回答（2 个）
In this context, it appears to be deleting elements from A.
Try it out in MATLAB to see what it is doing.
A = rand(3)
A(1,:)=[]
A(i,:) = [];
This deletes the i.th row of the matrix A.
Example:
A = [1,2,3; 4,5,6; 7,8,9];
A(1, :) = []
% A = [4,5,6; 7,8,9]
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