find if one number is member of a column ,of cell array, that contains cell entries and if it is member, in which row, it appears
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I have a 23*6 cell array that is called cofPairs.
As you see, the 5th and 6th column contain cell entries, that contain numbers. For example, the first element of the 5th column ( cofPairs{1,5} )
So, what I want to do.
I want to check for several random numbers if they appear in any entry in the 5th column of the array. I want also to know in which rows of the 5th column appear (in any entry).
How can I achieve this?
Thank you!
1 个评论
Jan
2021-11-14
It would be more efficient to store the numbers inb a numerical vector instead of a column cell, which contains scalars.
采纳的回答
Jan
2021-11-14
编辑:Jan
2021-11-14
Simplify the data representation at first:
for k = 1:size(C, 1)
C{k, 5} = [C{k, 5}{:}];
end
Then the searching is easy:
x = 17;
found = false(size(C, 1), 1);
for k = 1:size(C, 1)
found = any(C{k, 5} == x);
end
Now use found of find(found) as you want.
If you have a good reason to let the elements of the 5.th row be a cell (e.g. if the elements are vectors of different sizes in opposite of the shown example, in which they are scalars):
x = 17;
found = false(size(C, 1), 1);
for k = 1:size(C, 1)
found = any([C{k, 5}{:}] == x);
end
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