Trying to fix the loop

Question

Cameron Paterson 2021-11-16

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1588169-trying-to-fix-the-loop

编辑： Jan 2021-11-16

I am trying to change my code so when it loops more than five times the error message changes to Invalid vehicle type! Re-enter vehicle type (Compact, Midsize, Truck, Industrial, Military)

I have been trying to just use the variable n>5 under the for loop for this but keep getting error messages

Vehicle_Type=input('Enter the Vehicle Type','s')

for n=1:5

switch Vehicle_Type

case{'compact','Compact'}

fprintf('1\n');

break

case{'midsize','Midsize'}

fprintf('2\n');

break

case{'truck','Truck'}

fprintf('3\n');

break

case{'industrial','Industrial'}

fprintf('4\n');

break

case{'military','Military'}

fprintf('4\n');

break

otherwise

fprintf('Vehicle type is not recognized. The program stops. Rerun the program again\n')

end

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Awais Saeed 2021-11-16

what actually are you trying to do? Your loop does not make any sense. Your user input should be inside the loop to ask for the input for all iterations.

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Answer 1

Jan 2021-11-16

0
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1588169-trying-to-fix-the-loop#answer_832954

编辑：Jan 2021-11-16

在 MATLAB Online 中打开

nFail = 0;
for n = 1:5
   Vehicle_Type = input('Enter the Vehicle Type', 's');
   switch lower(Vehicle_Type)
       case 'compact'
            fprintf('1\n');
            break
       case 'midsize'
            fprintf('2\n');
            break
       case 'truck'
            fprintf('3\n');
            break
       case 'industrial'
            fprintf('4\n');
            break
       case 'military'
            fprintf('4\n');
            break
       otherwise
            fprintf('Vehicle type is not recognized. The program stops. Rerun the program again\n');
            nFail = nFail + 1;
    end
end
if nFail == 5
  fprintf('bad\n');
end

I'd solve this without a for loop:

found = 0;
nFail = 0;
while ~any(found) && nFail < 5
   Vehicle_Type = input('Enter the Vehicle Type', 's');
   switch lower(Vehicle_Type)
       case 'compact'
            found = 1;
       case 'midsize'
            found = 2;
       case 'truck'
            found = 3;
       case {'industrial', 'military'}
            found = 4;
       otherwise
            fprintf('Vehicle type is not recognized. Again...\n');
            nFail = nFail + 1;
    end
end
if found
   fprintf('%d\n', found);
else
   fprintf('failed too often\n');
end