Trying to fix the loop

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Cameron Paterson
Cameron Paterson 2021-11-16
编辑： Jan 2021-11-16
I am trying to change my code so when it loops more than five times the error message changes to Invalid vehicle type! Re-enter vehicle type (Compact, Midsize, Truck, Industrial, Military)
I have been trying to just use the variable n>5 under the for loop for this but keep getting error messages
Vehicle_Type=input('Enter the Vehicle Type','s')
for n=1:5
switch Vehicle_Type
case{'compact','Compact'}
fprintf('1\n');
break
case{'midsize','Midsize'}
fprintf('2\n');
break
case{'truck','Truck'}
fprintf('3\n');
break
case{'industrial','Industrial'}
fprintf('4\n');
break
case{'military','Military'}
fprintf('4\n');
break
otherwise
fprintf('Vehicle type is not recognized. The program stops. Rerun the program again\n')
end
end
  1 个评论
Awais Saeed
Awais Saeed 2021-11-16
what actually are you trying to do? Your loop does not make any sense. Your user input should be inside the loop to ask for the input for all iterations.

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采纳的回答

Jan
Jan 2021-11-16
编辑：Jan 2021-11-16
nFail = 0;
for n = 1:5
Vehicle_Type = input('Enter the Vehicle Type', 's');
switch lower(Vehicle_Type)
case 'compact'
fprintf('1\n');
break
case 'midsize'
fprintf('2\n');
break
case 'truck'
fprintf('3\n');
break
case 'industrial'
fprintf('4\n');
break
case 'military'
fprintf('4\n');
break
otherwise
fprintf('Vehicle type is not recognized. The program stops. Rerun the program again\n');
nFail = nFail + 1;
end
end
if nFail == 5
fprintf('bad\n');
end
I'd solve this without a for loop:
found = 0;
nFail = 0;
while ~any(found) && nFail < 5
Vehicle_Type = input('Enter the Vehicle Type', 's');
switch lower(Vehicle_Type)
case 'compact'
found = 1;
case 'midsize'
found = 2;
case 'truck'
found = 3;
case {'industrial', 'military'}
found = 4;
otherwise
fprintf('Vehicle type is not recognized. Again...\n');
nFail = nFail + 1;
end
end
if found
fprintf('%d\n', found);
else
fprintf('failed too often\n');
end

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