I have problem with while loop.

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Tran Thien
Tran Thien 2021-11-17
评论： Chunru 2021-11-17
So I have homework about Gaussian Elimination, when input matrix b I want to ensure that the input matrix has the same number of rows as matrix A and it must be in a column matrix so I tried these code with while loop:
A=input('Input matrix A');
b=input('Input matrix b in column form');
szA=size(A)
szb=size(b)
while (szb(1,1)~=szA(1,1) && szb(1,2)~=1)
b=input('Matrix b is not in column form,please re-input');
szb=size(b)
if (szb(1,1)==szA(1,1)&& szb(1,2)==1)
break
end
end
Ab=[A b]
My goal here is when the input matrix b has a different number of rows than that of matrix A and/or the number of columns is not equal to 1 then the user has to re-enter the matrix. When both conditions are met then break the while loop and continue.
But when I tested with matrices like:
A=[1 2;2 1] b=[1 2;2 1]
The while loop still break and give me matrix Ab.
Or
A=[1 2;2 1] b=[1;2;3]
The while loop breaks and the program gives me the horzcat error (I understand that matrix b don't have the same number of rows as matrix A will cause this error)
Please help. Thank you.

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采纳的回答

Chunru
Chunru 2021-11-17
Make the following change:
%while (szb(1,1)~=szA(1,1) && szb(1,2)~=1)
while (szb(1,1)~=szA(1,1) || szb(1,2)~=1)
  2 个评论
Tran Thien
Tran Thien 2021-11-17
It works! Thank you very much.
Chunru
Chunru 2021-11-17
To make your code easer to read, you can chnage szb(1,1) to szb(1) and so on.

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