"Check for incorrect argument data type or missing argument in call to function 'X'. Error in sum=sum+A(j,h)*X(h)

Question

Avelon Jr Eugenio 2021-12-5

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1603295-check-for-incorrect-argument-data-type-or-missing-argument-in-call-to-function-x-error-in-sum-s

评论： Avelon Jr Eugenio 2021-12-5

output= ('Gaussian Elimination Method')
A=input ('Enter your coefficient Matrix')
b=input ('Enter your space vector')
N=length(b);
x=zeros(N,1);
for j=1:1:N-1 %Forward Elimination
    for i = j+1:1:N
        m=A(i,j)/A (j,j);
        A(i,:)=A(i,:)- m*A(j,:)
        b(i) = b(i) - m*b(j)
    end
end
disp([A,b]);
for j=N:-1:1%Backward Elimination
    sum=0;
    for h=1+1:1:N      
        sum=sum+A(j,h)*X(h);
    end
    X(j)=(b(j)-sum)/A(j,j);
end
disp(X);

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Answer 1

Chunru 2021-12-5

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1603295-check-for-incorrect-argument-data-type-or-missing-argument-in-call-to-function-x-error-in-sum-s#answer_847850

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output= ('Gaussian Elimination Method')
output = 'Gaussian Elimination Method'
% A=input ('Enter your coefficient Matrix')
% b=input ('Enter your space vector')
A = randn(3,3);
b = randn(3,1)
b = 3×1
   -1.0379
    0.3246
    0.2563
N=length(b);
X=zeros(N,1);       % upper case X (use case carefully)
for j=1:1:N-1 %Forward Elimination
    for i = j+1:1:N
        m=A(i,j)/A (j,j);
        A(i,:)=A(i,:)- m*A(j,:)
        b(i) = b(i) - m*b(j)
    end
end
A = 3×3
   -1.6440    0.8403   -0.7771
         0   -1.4609   -0.1171
   -0.6397    0.9495   -0.2362
b = 3×1
   -1.0379
    0.4488
    0.2563
A = 3×3
   -1.6440    0.8403   -0.7771
         0   -1.4609   -0.1171
         0    0.6225    0.0662
b = 3×1
   -1.0379
    0.4488
    0.6602
A = 3×3
   -1.6440    0.8403   -0.7771
         0   -1.4609   -0.1171
         0         0    0.0163
b = 3×1
   -1.0379
    0.4488
    0.8514
disp([A,b]);
   -1.6440    0.8403   -0.7771   -1.0379
         0   -1.4609   -0.1171    0.4488
         0         0    0.0163    0.8514
for j=N:-1:1%Backward Elimination
    s=0;          % try not use sum as variable as it is a built in function
    for h=1+1:1:N      
       s=s+A(j,h)*X(h);
    end
    X(j)=(b(j)-s)/A(j,j);
    end
disp(X);
  -26.3721
   -4.4960
   52.2675