how to add one space to a matrix ?

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janny 2014-11-9

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评论： janny 2014-11-10

am using this code to generate binary matrix dec2bin(rand(50,1)*2^32) but i need to add one space between the matrix element so i can use it for other commands. the output matrix needs space to be useful for other calculation. how to do this?

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Answer 1

Guillaume 2014-11-9

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编辑：Guillaume 2014-11-9

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The following would work:

m =  dec2bin(rand(50,1)*2^32)
mwithspaces = cell2mat(regexprep(num2cell(m, 2),'\d(?=\d)', '$0 '));

I have to ask though, why do you want to do that? It seems like an unnecessary step. I would think that any algorithm that follows is probably going to remove these spaces one way or another.

edit: was missing a bracket

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Guillaume 2014-11-9

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As commented on Jan's answer, inserting spaces is a red herring. To convert a string of zeros and ones into a matrix of zeros and ones numbers, simply subtract '0' from the string.

This may be what you're looking for:

M = dec2bin(rand(10, 1) * 2^32);
M = M - '0'; %convert M into an array of numbers 0 or 1
[m, n] = size(M);
M2 = [zeros(m, 3*ceil(n/3)-n), M];
X = xor(xor(M2(:, 1:3:end-2), M2(:, 2:3:end-1)), M2(:, 3:3:end))

janny 2014-11-10

it works fine... thanks a lot....

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Answer 2

Jan 2014-11-9

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编辑：Jan 2014-11-9

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s = dec2bin(rand(50,1)*2^32);
t = repmat(' ', size(s, 1), size(s, 2) * 2 - 1);
t(:, 1:2:end) = s;

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janny 2014-11-9

编辑：janny 2014-11-9

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i'm writing an algorithm to calculate CA rule 150 from this sequence, so when i try these codes didn't give the right answer, this is my code:

M = dec2bin(rand(10,1)*2^32);

[m,n] = size(t);

   M2 = [zeros(m,3*ceil(n/3)-n),t];
   X = xor(xor(M2(:,1:3:end-2),M2(:,2:3:end-1)),M2(:,3:3:end))

if : M = [0 0 0 1 1 1 1 1 1 0 1 1 1 0 1 0 0 0 0 0 0 1 1 0 1 0 0 1 0 1 1 1]

then X = 0 0 1 0 0 1 0 0 1 1 1

so how to make it run?

Guillaume 2014-11-9

编辑：Guillaume 2014-11-9

I don't know what CA rule 150 is so why don't you explain it.

It is now clear however, that your original question is a case of xy problem. Looking at your attempted code, you don't need to insert spaces and actually want to operate on numbers rather than strings.

xor certainly does not work with strings.

See comment on my own answer for a possible solution.

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