Storing data from 2 lines of text

Question

Sebastian Ciuban 2014-11-10

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/162112-storing-data-from-2-lines-of-text

编辑： Guillaume 2014-11-11

Hello there, I have this text

10           NAVIGATION DATA                         RINEX VERSION / TYPE
SPIDER V4,3,0,4633  NACLR               2013 03 13 00:04    PGM / RUN BY / DATE 
1420D-08  7.4506D-09 -1.1921D-07  0.0000D+00           ION ALPHA           
2288D+05  0.0000D+00 -2.6214D+05  1.9661D+05           ION BETA            
656612873077D-09 1.687538997430D-14   503808     1731 DELTA-UTC: A0,A1,T,W
                                                    LEAP SECONDS        
                                                        END OF HEADER

I want to store in a matrix [2 x 4] the values from line 3 and 4..I have made this function but it only works for one line (line 3):

function [ephe] = readRINEXnav()
[file,path] = uigetfile('*.**n'); 
fid = fopen(strcat(path,file),'r');
for tline=1:3
tline = fgets(fid);
Iono_alpha=[str2num(tline(3:13)) str2num(tline(15:25)) str2num(tline(26:37))...
          str2num(tline(39:49))];
end
end

I know it is rudimentary, I'm still learning.

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Answer 1

Guillaume 2014-11-10

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https://ww2.mathworks.cn/matlabcentral/answers/162112-storing-data-from-2-lines-of-text#answer_158416

编辑：Guillaume 2014-11-10

在 MATLAB Online 中打开

Well, yes, you're reading the first three lines, of which the first two are mostly text only. So of course, it only works on the 3rd line.

You need to skip the first two lines before reading the next two. Two fgets or fgetl (I prefer the latter) would take care of that.

Note that I wouldn't hardcode the position of the numbers in each line as that's quite fragile. I would just detect the position of the two '*' and extract the portion of text in between. str2num can then convert all the numbers in between in one go:

%...
fid = fopen(fullfile(path, file), 'rt'); %fullfile is better than strcat, 'rt' for text file
fgetl(fid); fgetl(fid); %skip first two lines
for lcount = 1:2
   tline = fgetl(fid);
   starpos = find(tline == '*');
   assert(numel(starpos) == 2, 'line %d does not have two *', lcount+2);
   numbers{lcount} = str2num(tline(starpos(1)+1 : starpos(2)-1));
end
fclose(fid);
%...

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Sebastian Ciuban 2014-11-10

Sorry, "*" is not part of the text file..I have edited it..

Guillaume 2014-11-11

编辑：Guillaume 2014-11-11

在 MATLAB Online 中打开

Well then, it's even simpler. You could just hardcode the start and end of the number portion of each line. Thus the inside of the loop becomes:

tline = fgetl(fid);
numbers{lcount} = str2num(tline(1:46)); %or whatever the bounds are

However, to give more flexibility, in this case I would use a regular expression to find the numeric portion of each string. I believe the following would work for you:

tline = fgetl(fid);
numpart = regexp(tline, '(?:[+-]?\d*\.?\d+(?:D[+-]\d+)? *)*', 'match', 'once'); 
numbers{lcount} = str2num(numpart);

Incidentally, str2num seems to be the only string to numeric conversion function in matlab to understand the D part of your strings. Neither sscanf nor str2double accept it.

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