Reshaping Structure in every iteration

2022 2 8
1 个回答
更新时间：2022 2 9
1 次查看（30 天）

0 个投票

Hi
I'm iterating a loop. And in each iteration, i make random numbers by using rand function. And in every new iteration, I increase the size of matrix (which is created by rand function).
What i'm doing is storing every random matrix in structure in every iteration. So, what i need is to reshape the structure in every iteration.(to be Rows*1).
My question is, how can i reshape the structure ?
I'll really appreciate it if some one can help me with that.
Thanks a lot.

7 个评论
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Jan
Jan 2022-2-8
What do you call "structure"? A STRUCT array? A struct containing arrays as fields? Please post the current code.
mohammad rashidi
mohammad rashidi 2022-2-8
编辑：Jan 2022-2-8
R=5;
for i=1:10
M(:,i).position=rand(R,1);
R=R+10;
end
This is not what i'm working on , but that's similar.
Thank you.
Benjamin Thompson
编辑：Jan 2022-2-8
Your code seems to work. What specifically needs to be changed in the behavior?
>> R=5;
for i=1:10
M(:,i).position=rand(R,1);
R=R+10;
end
>> M
M =
1×10 struct array with fields:
position
mohammad rashidi
mohammad rashidi 2022-2-8
As every random matrix has different rows, i want to gather all matrices in one matrix with the size of " rows*1 " at the end of each iteration.
Jan
Jan 2022-2-8
It is still not clear. In each iteration only one matrix is created. What does "all matrices at the end of each iteration" mean then? What is "rows"? Do you want to append each new matrix to the existing one?
V = [];
for i = 1:10
V = cat(1, V, rand(5 + 10 * (i - 1), 1));
M(i).position = V ;
end
mohammad rashidi
mohammad rashidi 2022-2-8
Exactly, i wanna append them. What i mean by " rows*1" is , i want to just have a final matrix with one column.
Jan
Jan 2022-2-8
Okay, then I post this code as an answer.

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回答（1 个）

Jan
Jan 2022-2-8

1 个投票

V = [];
for i = 1:10
V = cat(1, V, rand(5 + 10 * (i - 1), 1));
M(i).position = V ;
end

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