Suppression failure on evalin command

4 次查看（过去 30 天）
Ian
Ian 2014-11-28
编辑： Jan 2017-8-12
I'm having a problem suppressing the evalin function when using it to change elements in a vector. The semi-colon isn't working. Is there a fix for this? Here's an example:
>> i=zeros(1,4);
>> evalin('base','i(1)=1');
i =
1 0 0 0
The semicolon doesn't suppress the output for some reason.

请先登录，再回答此问题。

采纳的回答

Mischa Kim
Mischa Kim 2014-11-28
编辑：Mischa Kim 2014-11-28
Ian, put the semi-colon right after the i(1)=1 statement
evalin('base','i(1)=1;')

更多回答（2 个）

Jan
Jan 2017-8-11
编辑：Jan 2017-8-12
It would be much more simple and efficient to omit the indirection over evalin:
i(1) = 1;
See the excellent explanations at tutorial:why-variables-should-not-be-named-dynamically-eval . You find a detailed analysis of the problems evalin causes here at: Answers: is-there-the-more-elegant-way-to-do-this#comment_476583
Ian
Ian 2014-11-28
So simple, yet so effective. Thanks!

类别

在 Help Center 和 File Exchange 中查找有关 App Building 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by