Error: Operator '-' is not supported for operands of type 'function_handle'.

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Hello, i have the following Code:
f1 = [-1,-1];
f2=@(x)-10*x(1)+x(1)^2-4*x(2)+x(2)^2;
A = [3 1;
2 1 ;
1 2];
b = [12; 9; 12];
z = [0,0];
d = [-1,0];
Method(f1,f2,A,b,z,d);
function [x,alpha] = Method(f1,f2,A,b,z,d)
f =@(x)-x(size(A,2)+1);
x0 = (zeros(1,size(A,2) + 1));
lb = [(zeros(1,size(A,2))),-Inf];
if (~isempty(f1))
Anew = [f1,-d(1)];
Anew(2:size(A,1)+1,1:size(A,2)) = A;
bnew = [z(1);b];
c1 =@(x) f2 - d(2)*x(size(A,2)+1) - z(2);
(else ... %in this case Anew,bnew and c1 would look different)
end
nonlincon = @constr;
function [c,ceq] = constr(x)
c = c1;
ceq = [];
end
[x,alpha]=fmincon(f,x0,Anew,bnew,[],[],lb,[],nonlincon);
end
This gives me the following error: Operator '-' is not supported for operands of type 'function_handle'.
I know that it is because of the line "c1 =@(x) f2 - d(2)*x(size(A,2)+1) - z(2);". Does someone knows how i could solve this problem? Thanks.
  2 个评论
David Hill
David Hill 2022-2-10
A general description of what you are trying to do with inputs and expected outputs would be helpful. I cannot follow your code (lots of problems).
Daniela Würmseer
Daniela Würmseer 2022-2-10
It is a part of a specific Algorithm. I want to use the fmincon function to solve a nonlinear Problem. At the beginning f1, f2, A,b,z and d are given. But inside the function "Method" we want to change this problem still a bit before giving it into fmincon.

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采纳的回答

Star Strider
Star Strider 2022-2-10
To be used in calculations, functions must be evaluated, and that means providing them with an argument.
See if this provides the desired result:
c1 =@(x) f2(x) - d(2)*x(size(A,2)+1) - z(2);
I am confindent that will work and not throw the previous error. I have not tested the code with this correction.
.
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