Convert nearly created string in a structure format to a variable name in a for loop

Question

Goldie 2014-11-30

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/164801-convert-nearly-created-string-in-a-structure-format-to-a-variable-name-in-a-for-loop

评论： Goldie 2014-11-30

Hey there,

I been trying to convert a nearly created string to a variable in a for loop and I cam struggling to find the correct function to convert it.

I have included a simple example problem below which details the problem. Thanks in advance for your help

if true
 close all 
clear all 
clc
% Two cars referened as Car01 and Car02 are studied
% Two variables are recored 1st column=  time (s),  2nd column =  distanc (m)
A.Car01.speed = [1 2 3 4 5; 10 20  30  40 50 ]'; 
A.Car02.speed = [1 2.1 3.3 4.5 5; 11 19  33  42 51]';
% Want to interpolate the distance of both cars travelled in a loop
for  k=1:2
  % Create a mat filename, and load it into a structure called matData.
   matFileName = sprintf('A.Car%02d.speed', k);
  temp_col = (eval(matFileName));
  temp_time = temp_col(:,1);
  temp_speed = temp_col(:,2);
  Final_lenght = 10;
  Interpolation_f = temp_time(end)/Final_lenght; 
  Interp_time = 0:Interpolation_f:temp_time(end);     
  temp_speed  =  interp1(temp_time,temp_speed,Interp_time);
  temp_name = sprintf('A.Car%02d.speed_interp', k);  
  % I want to save the newly created variable A.Car01.speed_interp =
  % temp_speed and A.Car02.speed_interp as the other calculated speed in
  % the for loop  
  %  cellstr(temp_name) =  temp_speed does not work    
end 
end

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Answer 1

Mohammad Abouali 2014-11-30

1
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/164801-convert-nearly-created-string-in-a-structure-format-to-a-variable-name-in-a-for-loop#answer_160692

编辑：Mohammad Abouali 2014-11-30

在 MATLAB Online 中打开

I code it something like this: (note the use of ( ) while referencing structure fields with string, such as A.(carNumber).speed where carNumber is 'Car01'

clear all 
clc
A.Car01.speed = [1 2 3 4 5; 10 20  30  40 50 ]'; 
A.Car02.speed = [1 2.1 3.3 4.5 5; 11 19  33  42 51]';
for  k=1:2
  carNumber = sprintf('Car%02d', k);  
  temp_time = A.(carNumber).speed(:,1);
  temp_speed = A.(carNumber).speed(:,2);
  Final_lenght = 10;
  Interpolation_f = temp_time(end)/Final_lenght; 
  Interp_time = 0:Interpolation_f:temp_time(end);     
  A.(carNumber).speed_interp  =  interp1(temp_time,temp_speed,Interp_time);
end

By the way, this way of interpolating will have some NaN in the beginning. Your time data vector starts from 1 but when interpolating you start Interp_time from 0. I did not changed that assuming that is what you want.