How to fprintf a transposed matrix?

3 次查看(过去 30 天)
Hello, I am trying to use fprintf to show the values of a transposed matrix. However, it does not seem to show the values as I would hope.
A = [7 11; 15 23; 9 7];
T=A.';
fprintf('\n A''= \n');
fprintf(' %d \t %d \t %d\n',T);
The result will be;
7 11 15
23 9 7
But I am expecting;
7 15 9
11 23 7

回答(2 个)

Stephen23
Stephen23 2022-2-16
编辑:Stephen23 2022-2-16
fprintf(..,T.');
% ^^
Or skip T entirely:
fprintf(..,A);
In MATLAB, just like in many other mathematical computation languages (e.g. FORTRAN), array elements are stored going down the rows first, then along the columns, etc.
When you process data in linear order (e.g. as FPRINTF does), you always need to take into account the order that the data are actually stored in memory.

Jan
Jan 2022-2-16
fprintf takes the argument elementwise as they are store in the memory. So:
A = [7 11; 15 23; 9 7];
fprintf(' %d \t %d \t %d\n', T);
is equivalent to:
fprintf(' %d \t %d \t %d\n', T(:));
Transposing the matrix is the solution, as Stephen has answered already.

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