combining elements in array

Question

pallavi patil 2022-2-18

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1653110-combining-elements-in-array

编辑： Voss 2022-2-18

采纳的回答： Voss

A= [1 1 1 0 1 1 0 0 ]

A2 = [1 0 1 0]

A3 = [ 1 0 ? ]

A4 = [0 0]

In this , array has either ones or zeros. Array A2 is created by applying and logic on A(1) & A(2)., next elementt in A2 is A(3) & A(4) so on ....

Array A3 is created by anding A(1)& A(2) & A(3), next element is A(4)& A(5) & A(6)

Array A4 is created by anding A(1)& A(2) & A(3) & A(4).

I want to create such arrays which will go to length of the vector A. Like Array A8 = A(1)& A(2) & A(3) & A(4)& A(5) & A(6)& A(7)& A(8).

my code is

%%%%%%%%

for A2

sz = length(A);

if rem(sz,2)==1

d1 = reshape(A(1:end-1,:),2,[]);

A2 = [d1(1,:)&d1(2,:)]';

end

%%%%%%%%%

%for A3

if (mod(sz,3)==2)

d1 = reshape(A(1:end-2,:),3,[]);

A3 = [d1(1,:)&d1(2,:)&d1(3,:)]';

elseif (mod(sz,3)==1)

d1 = reshape(A(1:end-1,:),3,[]);

A3= [d1(1,:)&d1(2,:)&d1(3,:)]';

else(mod(sz,3)==0)

d1 = reshape(A,3,[]);

A3= [d1(1,:)&d1(2,:)&d1(3,:)]'

end

%%%%%%%%%%%%

%for A4

if rem(sz,4)==3

d1 = reshape(A(1:end-3,:),4,[]);

A4 = [d1(1,:)&d1(2,:)&d2(3,:)&d1(4,:)]';

elseif rem(sz,4)==2

d1 = reshape(A(1:end-2,:),4,[]);

Yval_pred4 = [d1(1,:)&d1(2,:)&d1(3,:)&d1(4,:)]';

elseif rem(sz,4)==1

d1 = reshape(A(1:end-1,:),4,[]);

A4 = [d1(1,:)&d1(2,:)&d1(3,:)&d1(4,:)]';

else

d1 = reshape(A,4,[]);

A4= [d1(1,:)&d1(2,:)&d1(3,:)&d1(4,:)]';

end

Is there a simpler way to do this. I have very long A aray and i cant apply divisibilty test for evrery number to get A5, A6, A7 array and so on

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Answer 1

Voss 2022-2-18

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1653110-combining-elements-in-array#answer_899490

编辑：Voss 2022-2-18

在 MATLAB Online 中打开

A= [1 1 1 0 1 1 0 0 ];
M = 2; % number of elements of A to group together in sets
N = numel(A);
d = reshape(A(1:N-rem(N,M)),M,[]);
new_A = all(d,1)
new_A = 1×4 logical array
   1   0   1   0

Using that same construction in a loop over different M values can allow you to do several easily:

A= [1 1 1 0 1 1 0 0 ];
N = numel(A);
M = 1:N; % for example
new_A = cell(1,numel(M));
for m = 1:numel(M)
    new_A{m} = all(reshape(A(1:N-rem(N,M(m))),M(m),[]),1);
end
disp(new_A);
    {[1 1 1 0 1 1 0 0]}    {[1 0 1 0]}    {[1 0]}    {[0 0]}    {[0]}    {[0]}    {[0]}    {[0]}