time conversion

3 次查看（过去 30 天）
Uday
Uday 2011-9-23
I have some data which says that the available time is in fraction days since 01:01:2000 and another data has time in seconds , so somebody please tell me how I can convert this data to [Year Month Day Hour Minute Second format].

请先登录，再回答此问题。

采纳的回答

Jan
Jan 2011-9-23
DATENUM is a serial date format, which starts at 00-Jan-000. The integer part is the number of days, the fraction part is the time of the day divided by 86400. If I understand you question correctly, you need to add datenum('01-Jan-2000') to your time in "fraction day" and let datevec convert the serial date to a date vector.
If this does not help, please post an example of the input and output dates.
  4 个评论
显示 2更早的评论
Uday
Uday 2011-9-23
I used following codes
is it correct method ?
time=datenum(sec/86400+datenum('01-Jan-2005'));
Time_N=datevec(time); % here we can get [Year Month Day Hour Minute Second ]
Walter Roberson
Walter Roberson 2011-9-23
That should be fine -- but watch out for leap seconds. MATLAB does not deal well with leap seconds.

请先登录，再进行评论。

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Dates and Time 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by