accuracy n precision
显示 更早的评论
采纳的回答
更多回答(1 个)
UJJWAL
2011-9-26
Hi
The problem with MATLAB is its precision in these cases. You can try like this .
cosd(x * (180/pi));
% Where x is the angle in radians
This will give you the correct result.
For example when x = pi/2 then cosd (pi/2 * 180/pi) = 0
类别
在 帮助中心 和 File Exchange 中查找有关 Resizing and Reshaping Matrices 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!