random assignment to 1s in a matrix

Question

Berfin Çetinkaya 2022-3-16

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1672939-random-assignment-to-1s-in-a-matrix

评论： Berfin Çetinkaya 2022-3-16

采纳的回答： Jan

c= birincifaz(:,:)

x=find(c==1)

ja=randi(613,1)

c(x(ja))= randi(10,1)

Hi. I have set up such code. My matrix is very large in 10x69 structure, I want to assign a random number from one to eighteen where 1 is written in the matrix. and it takes too long to assign manually so I want to assign by code. I was able to assign 1 to 1 with this code. How can I set up code about assigning to other 1's? ( Caution ! I wrote birincifaz values below.)

thanks a lot of

birincifaz=

1 1 1 1 1 0 1 1 1 1

0 0 0 0 0 0 1 1 1 1

1 1 1 1 1 0 1 1 1 1

1 1 0 1 1 0 1 1 1 1

1 1 1 1 1 0 1 1 1 1

1 1 1 1 1 1 1 1 1 1

1 1 1 1 1 0 1 1 1 1

1 1 1 1 1 1 1 1 1 1

1 1 1 1 1 0 1 1 1 1

0 0 0 0 0 0 1 0 0 0

1 1 1 1 1 0 1 1 1 1

1 1 1 1 1 1 1 1 1 1

1 1 1 1 1 0 1 1 1 1

1 1 1 1 1 1 1 1 1 1

0 0 0 0 0 0 1 1 1 1

1 1 1 1 1 1 1 1 1 1

1 1 1 1 1 0 1 1 1 1

1 1 1 1 1 1 1 1 1 1

0 0 0 0 0 0 1 0 0 0

1 1 1 1 1 1 1 1 1 1

1 1 1 1 1 0 1 1 1 1

1 1 1 1 1 1 1 1 1 1

0 0 0 0 0 0 1 0 0 0

1 1 1 1 1 1 1 1 1 1

1 1 1 1 1 0 1 1 1 1

1 1 1 1 1 1 1 1 1 1

1 1 1 1 1 0 1 1 1 1

1 1 1 1 1 1 1 1 1 1

1 1 1 1 1 0 1 1 1 1

1 1 1 1 1 1 1 1 1 1

1 1 1 1 1 0 1 1 1 1

1 1 1 1 1 1 1 1 1 1

1 1 1 1 1 0 1 1 1 1

1 1 1 1 1 1 1 1 1 1

1 1 1 1 1 0 1 1 1 1

1 1 1 1 1 1 1 1 1 1

1 1 1 1 1 0 1 1 1 1

1 1 1 1 1 1 1 1 1 1

1 1 1 1 1 0 1 1 1 1

1 1 1 1 1 1 1 1 1 1

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Answer 1

Jan 2022-3-16

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https://ww2.mathworks.cn/matlabcentral/answers/1672939-random-assignment-to-1s-in-a-matrix#answer_919034

编辑：Jan 2022-3-16

在 MATLAB Online 中打开

I do not understand the question:

"I was able to assign 1 to 1 with this code." - what is the purpose of setting a 1 to a 1?

"How can I set up code about assigning to other 1's?" - which other 1's? Ah, you have changed one single 1 and want to change all. Then:

c = birincifaz;  % No need for: (:,:), no need for FIND.
c(c == 1) = randi(18, 1, nnz(c))

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Berfin Çetinkaya 2022-3-16

This is the correct answer! Thank you so much.

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Answer 2

Davide Masiello 2022-3-16

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1672939-random-assignment-to-1s-in-a-matrix#answer_919039

编辑：Davide Masiello 2022-3-16

在 MATLAB Online 中打开

c = randi([0,1],69,10)                     % This replaces your biricinfaz, didn't want to copy that ;)
c = 69×10
   0     0     0     1     1     1     0     0     0
   0     0     0     1     1     1     0     1     1
   0     1     1     1     1     0     1     0     0
   0     1     1     0     1     1     1     1     1
   0     1     0     0     0     1     0     1     0
   0     0     0     1     0     1     0     0     1
   1     1     1     0     1     1     1     0     1
   1     0     1     0     0     1     1     0     0
   1     0     1     1     1     0     1     1     1
   1     0     0     0     1     1     0     0     0
c(logical(c)) = randi(18,sum(c(:)),1)      % This insert random values up to 18 in place of the 1s in c
c = 69×10
   0     0     0    13     6    14     0     0     0
   0     0     0     8    11    13     0     7    14
   0    13     3    10    17     0    11     0     0
   0     7     2     0     2     1     7     7    16
   0     8     0     0     0    14     0    12     0
   0     0     0    10     0     6     0     0     3
   2     7     8     0     9     5     6     0     6
  16     0    13     0     0     8    12     0     0
  14     0    18    11     3     0    11     9     3
  10     0     0     0    10     6     0     0     0