How to do it more efficiently?
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Hi,
In my script, this piece of code is taking about 70% of processing time.
The idea is to create uniform timestamp, it searches the time array and compare it with the Tsynced. if there is no similar entry, the other parameters to NaN.
Is there anyway to change the script below without using find function? Even better if no for-loop is required.
Code:
for ix = 1:length(time_synced)
[r,~,~] = find(cCells(:,1)==time_synced(ix),1,'first');
if isempty(r)
curArr(ix,:) = NaN;
else
curArr(ix,:) = cCells(r,:);
end
end
Thanks.
采纳的回答
Roger Stafford
2014-12-23
See if this is faster:
[t,ic] = ismember(time_synced,cCells(:,1));
curArr(t) = cCells(ic);
curArr(~t) = NaN;
Note: This assumes that 'time_synced' and 'curArr' are vectors of the same length.
更多回答（1 个）
Andrei Bobrov
2014-12-23
[l0,ii] = ismember(time_synced,cCells(:,1));
out = nan(numel(time_synced),size(cCells,2));
out(l0,:) = cCells(ii(l0),:);
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