Cut a picture as needed

Question

tao wang 2022-3-26

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1681219-cut-a-picture-as-needed

评论： tao wang 2022-3-26

For example, I want to cut the picture into 9 pictures. I want to use the for loop, and then save the cut image into variables A1, A2,,, an. In this way, how do I in AI in the for loop change with the loop? I know how to save it locally, but I want to save it into the workspace. Thank you. I'd appreciate it if you can give an example

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Matt J 2022-3-26

2
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1681219-cut-a-picture-as-needed#answer_927459

编辑：Matt J 2022-3-26

在 MATLAB Online 中打开

Download mat2tiles and then,

Image=rand(900);
A=mat2tiles(Image,[300,300])
A = 3×3 cell array
    {300×300 double}    {300×300 double}    {300×300 double}
    {300×300 double}    {300×300 double}    {300×300 double}
    {300×300 double}    {300×300 double}    {300×300 double}

4 个评论
显示 2更早的评论隐藏 2更早的评论

Matt J 2022-3-26

编辑：Matt J 2022-3-26

在 MATLAB Online 中打开

Each element in the array is in decimal form, but shouldn't the image be an integer?

If you gave mat2tiles an integer array, the cells should be of that type as well.

Image=randi(255,900,'uint8');
mat2tiles(Image,[300,300])
ans = 3×3 cell array
    {300×300 uint8}    {300×300 uint8}    {300×300 uint8}
    {300×300 uint8}    {300×300 uint8}    {300×300 uint8}
    {300×300 uint8}    {300×300 uint8}    {300×300 uint8}