why it will go wrong using 'cell'?
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Recently, I ran two codes as follow:
a={[],[]};a{1}(a{1}==3)=[];
% it will go wrong
b=cell(1,2);b{1}(b{1}==3)=[];
2 个评论
The difference is the space allocated for each.
a={[],[]};
b=cell(1,2);
whos a b
warnerchang
2022-3-31
采纳的回答
I confirm, that this is an inconsistent behavior.
a = {[], []};
b = cell(1, 2);
isequal(a, b)
a{1}([]) = [] % Working: Nothing is deleted as expected
b{1}([]) = [] % Failing:
Both methods create a cell array of the same size, but cell() fills the elements with a NULL pointers, while {[], []} creates empty matrices. Matlab should treat NULL pointers as empty matrices, but as you see in this example, this exception has been forgotten sometimes. You cannot detect the NULL points from inside Matlab, but on the C level this is easy. KSSV's method to check the used memory is a strong hint also.
Report this bug to MathWorks. The function for deleting will be updated than to catch this exception.
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