Anonymous function arguments and parameters extrction
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If I have the anonymous function:
pu = @(x, y) [x,y];
is it npossible to extract the value of the argument x after the function has acted on it?
(Apologies if this does not make sense)
回答（2 个）
As written, as long as you know how long either one of the inputs was, yes.
P = @(x, y) [x, y];
x1 = 1:5;
y1 = 6:10;
z = P(x1, y1)
x2 = z(1:5); % I know how long x was, extract that many elements from z
isequal(x2, x1)
x3 = z;
x3(end-4:end) = []; % I know how long y was, remove that many elements from z
isequal(x3, x1)
pu = @(x, y) [x,y];
a = pu(1, 2:3)
b = pu(1:2, 3)
isequal(a, b)
This means: No, you cannot decide, what the inputs have been based on the output.
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