Anonymous function arguments and parameters extrction

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Ken
Ken 2022-4-1
回答： Jan 2022-4-1
If I have the anonymous function:
pu = @(x, y) [x,y];
is it npossible to extract the value of the argument x after the function has acted on it?
(Apologies if this does not make sense)

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回答（2 个）

Steven Lord
Steven Lord 2022-4-1
Ran in:
As written, as long as you know how long either one of the inputs was, yes.
P = @(x, y) [x, y];
x1 = 1:5;
y1 = 6:10;
z = P(x1, y1)
z = 1×10
1 2 3 4 5 6 7 8 9 10
x2 = z(1:5); % I know how long x was, extract that many elements from z
isequal(x2, x1)
ans = logical
1
x3 = z;
x3(end-4:end) = []; % I know how long y was, remove that many elements from z
isequal(x3, x1)
ans = logical
1
Jan
Jan 2022-4-1
Ran in:
pu = @(x, y) [x,y];
a = pu(1, 2:3)
a = 1×3
1 2 3
b = pu(1:2, 3)
b = 1×3
1 2 3
isequal(a, b)
ans = logical
1
This means: No, you cannot decide, what the inputs have been based on the output.

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