Legend colors match with plot
显示 更早的评论
Hi. I have a for loop in which I plot some curves with different colors.
P=[0.25 0.25 0.2 0.15 0.15];
color = {'r','c','g','y','b','m','k'};
for i=1:numel(P)
plot(1:N,nElemMat(:,i),color{i}); yline(P(i)); hold on;
end
I would like to have a legend in which each color represent the correspondent P(i) (red -> 0.25 , cyan -> 0.25, green -> 0.20,...).
I tried with
legend('0.25', '0.25', '0.2','0.15','0.15');
but colors don't match and I'm not using P.
Do you have any suggestion? Thanks
采纳的回答
Here is one way to code this (assuming I understand what you meant):
rng default
N = 3;
P=[0.35 0.25 0.2 0.15 0.10];
nElemMat = rand(N,numel(P));
color = {'r','c','g','y','b','m','k'};
figure
hold on
for i=1:numel(P)
plot(1:N,nElemMat(:,i),color{i})
hy(i) = yline(P(i));
set(hy(i),'Color',color{i})
end
legend(hy,color)
The code changes I made were
- Assign a handle to each yline, so that I could assign the color to each one. (This is the main thing you wanted.)
- Create the figure explicitly, and execute hold on just once.
- Define variables that you didn't have in your code, so I had a piece of self-contained code that would run.
- Changed the values of P, so you see every line
2 个评论
Rosario Frontino
2022-4-3
the cyclist
2022-4-3
编辑：the cyclist
2022-4-3
Sorry, I missed the part about a legend.
I've edited the code to show how to use the handles as an input to legend.
Note that the my code here is a bit weird, because I am using the handles to the horizontal lines, not to the plot lines themselves (but you seem to have a one-to-one correspondence, so that is OK). You could also have assigned handles to the plot lines themselves instead:
hp(i) = plot(...)
and assigned a legend based on those. That would be the norm, actually.
Also, I just used the color names themselves as the legend text. Obviously, you don't need to do that.
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Legend 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
