while loop for conditional statement

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sermet OGUTCU 2022-4-5

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1688959-while-loop-for-conditional-statement

评论： Jan 2022-4-6

array_data=33 x 1 % double
window_size=10;
m_BW=0.5;
var_BW=0.5;
for i=1:window_size
    m_BW(i+1)=(i/(i+1))*m_BW(i) + (1/(i+1))*BW(i+1);
    var_BW(i+1)= (i/(i+1))*var_BW(i) + (1/(i+1))*((BW(i+1)-m_BW(i))^2);
    if abs (BW(i+1)-m_BW(i)) >= sqrt(var_BW(i)) && abs (BW(i+2)-BW(i+1)) <= (1*lambda_wl)
        slip(i)=i;
    end
end

if this "if" statement is true, for example at i=5, then for loop needs to rebuild as:

for i=(5+1):(5+window_size)

if this "if" statement is not true, then for loop needs to continue as incremented by 10 as follows:

for i=(10+1):(10+window_size)

for loop needs to continue until all 10 batches within 33 x 1 array_data is completed. How I can write a compact code for the above statements regardless of the size of the array_data for saving all slip(i) data?

For another example, assuming that "if" statement is true for the first time at i=16 (for i= (10+1):(10+window_size) ), then, for i= (16+1):(16+window_size) needs to run for the last time within 33 x 1 data.

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MJFcoNaN 2022-4-5

Why don't you directly loop from 1 to a large number, such as 26?

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Answer 1

Jan 2022-4-5

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https://ww2.mathworks.cn/matlabcentral/answers/1688959-while-loop-for-conditional-statement#answer_935069

在 MATLAB Online 中打开

Maybe:

array_data=33 x 1 % double
window_size=10;
m_BW=0.5;
var_BW=0.5;
i = 1;
fin = window_size;
while i <= fin
    m_BW(i+1)   = i/(i+1) * m_BW(i) + (1/(i+1)) * BW(i+1);
    var_BW(i+1) = i/(i+1) * var_BW(i) + (1/(i+1)) * (BW(i+1)-m_BW(i))^2;
    if abs(BW(i+1) - m_BW(i)) >= sqrt(var_BW(i)) && abs(BW(i+2)-BW(i+1)) <= (1*lambda_wl)
        slip(i) = i;
        fin     = i + window_size;
    end
    i = i + 1;
end

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sermet OGUTCU 2022-4-5

编辑：sermet OGUTCU 2022-4-5

Dear @Jan, I run the code, but when the if condition becomes true the loop stops. If the "if " condition is true, the loop needs to goes on, but in your code, it seems that it stops. I stated this part in my question as follows:

if this "if" statement is true, for example at i=5, then for loop needs to rebuild as:

for i=(5+1):(5+window_size)

Jan 2022-4-6

Yes, this is exactly what my code does: If redefines the value of fin, such that the loop goes on.

But maybe I do not really understand, what you are asking for. At least my code could show you how to use a while loop. This allows to change the limits during the loop is running.

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