Hi everyone, I have a problem in my code
I'm trying to do an assignement between two array of dimension 3x1, but matlab told me everytime that it's impossible to do the operation because the size of the left term is 3-by-1 and the size of the right term is 3-by-0.. but during a debugging operation, I've controlled my right-side term and it is an array of 3x1.
basically, I have a function called EKF that picks as one of the input an array currentPose that is [1; 2; 3];
(in the main code, i give to the function the currentPose{1,1} that is effectively an array 3x1)
then inside this function it works like this:
EKF_p = zeros(3,2);
EKF_p(:,1) = currentPose;
EKF_p(:,2) = EKF_p(:,1) + dt*[cos(EKF_p(3,1)); sin(EKF_p(3,1)); omega];
and I get the error during this assignement.
Do anyone knows what the problem could be?
Thanks in advance

1 个评论

Please post some code, which reproduces the problem and a copy of the complete error message.
The show code looks fine, so I expect, the problem is somewhere else, where you do not expect it.

请先登录,再进行评论。

 采纳的回答

Jan
Jan 2022-4-20
编辑:Jan 2022-4-20
Let the debugger help you to analyse the problem. Type this in the command window:
dbstop if error
Then let the code run again. When it stops at the error, check the sizes of the right hand side again.

1 个评论

thank you so much for the answer! I didn't know this command!
The error was on another variable I was using during the operation
So thank you again and have a nice day

请先登录,再进行评论。

更多回答(0 个)

类别

帮助中心File Exchange 中查找有关 Software Development Tools 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by