Set same elements in a matrix to zero

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WEN SHIN LU
WEN SHIN LU 2022-4-25
回答： Matt J 2022-4-25
Hi,
I have a large matrix which has duplicate elements in neighborhood.
For example,
A = [0 0 0 01 1 0 0 0 2 2 2 0 0 0 5 5 5 5 5;
0 0 0 1 1 0 0 0 0 0 2 2 0 0 0 5 0 5 0 5;
0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 5 0 5 0]
I have to keep just a unique element in an arbitrary position. Could I use loop to solve this problem?
  2 个评论
Jan
Jan 2022-4-25
What is the wanted output for this example?
WEN SHIN LU
WEN SHIN LU 2022-4-25
sorry didn't explain clearly. The output can be:
A = [0 0 0 01 0 0 0 0 2 0 0 0 0 0 0 0 0 0 0;
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 5 0 0 0 0;
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]
I want to keep just one repeated element in its neighborhood.

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采纳的回答

Matt J
Matt J 2022-4-25
Ran in:
Without the Image Processing Toolbox,
A = [0 0 0 0 1 1 0 0 0 2 2 2 0 0 0 5 5 5 5 5;
0 0 0 1 1 0 0 0 0 0 2 2 0 0 0 5 0 5 0 5;
0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 5 0 5 0]
A = 3×20
0 0 0 0 1 1 0 0 0 2 2 2 0 0 0 5 5 5 5 5 0 0 0 1 1 0 0 0 0 0 2 2 0 0 0 5 0 5 0 5 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 5 0 5 0
[I,J,S]=find(A);
IJS=num2cell(splitapply(@(x) x(1,:), [I,J,S],findgroups(S)),1);
[I,J,S]=deal(IJS{:});
B=accumarray([I,J],S,size(A))
B = 3×20
0 0 0 0 0 0 0 0 0 2 0 0 0 0 0 5 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

更多回答（1 个）

Matt J
Matt J 2022-4-25
编辑：Matt J 2022-4-25
Ran in:
Something like this, perhaps?
A = [0 0 0 0 1 1 0 0 0 2 2 2 0 0 0 5 5 5 5 5;
0 0 0 1 1 0 0 0 0 0 2 2 0 0 0 5 0 5 0 5;
0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 5 0 5 0]
A = 3×20
0 0 0 0 1 1 0 0 0 2 2 2 0 0 0 5 5 5 5 5 0 0 0 1 1 0 0 0 0 0 2 2 0 0 0 5 0 5 0 5 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 5 0 5 0
reg=regionprops(A~=0,'PixelIdxList');
B=zeros(size(A));
for i=1:numel(reg),
j=reg(i).PixelIdxList(1);
B(j)=A(j);
end
B
B = 3×20
0 0 0 0 0 0 0 0 0 2 0 0 0 0 0 5 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0

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