How to merge multiple graphs/vectors in one!

Question

Ivan Shorokhov 2015-1-21

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/170970-how-to-merge-multiple-graphs-vectors-in-one

评论： Star Strider 2015-1-21

采纳的回答： Star Strider

在 MATLAB Online 中打开

Dear All,

Code used:

    figure; hold on; 
    plot(fliplr(x1), fliplr(y1), 'ro'); plot(x8, y8, 'rx');
    plot(fliplr(x2), fliplr(y2), 'bo'); plot(fliplr(x6), fliplr(y6), 'b*');
    plot(x3, y3, 'mo'); plot(x7, y7, 'mx');
    plot(x4, y4, 'co'); plot(fliplr(x5), fliplr(y5), 'c*');

Note: 1. Some of the values are NaN, 2. some of coordinate are clashes with each other. I would like to combine all 8 graphs into one graph(2 arrays Xtotal and Ytotal), how can I do it?

I could use following code to find all unique values:

    xall = [fliplr(x1) fliplr(x2) x3 x4 fliplr(x5) fliplr(x6) x7 x8];
    [x, ~, xindices] = unique(xall);
    yall = [fliplr(y1) fliplr(y2) y3 y4 fliplr(y5) fliplr(y6) y7 y8];
    [y, ~, yindices] = unique(yall);
>> x<1x102 double> = [258   259 ... 353   NaN]
>> y<1x189 double> = [177   178 ... 306   NaN]

But I'm not sure how I can use it, and what to do next. Also I would like to keep all NaN in the same place, if possible.

Thanks in advance for any help,

I

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Star Strider 2015-1-21

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/170970-how-to-merge-multiple-graphs-vectors-in-one#answer_165499

编辑：Star Strider 2015-1-21

在 MATLAB Online 中打开

To begin with, your data are apparently all row vectors, so I would concatenate them as cell arrays:

xall = {fliplr(x1); fliplr(x2); x3; x4; fliplr(x5); fliplr(x6); x7; x8};
yall = {fliplr(y1); fliplr(y2); y3; y4; fliplr(y5); fliplr(y6); y7; y8};
figure(1)
hold on
for k1 = 1:size(xall,1)
    plot(xall{k1}, yall{k1}, 'x')
end
hold off

I would not bother with unique, since the points will simply overplot each other, since you’re plotting them as discrete points and not as lines. In R2014b, the colours will cycle automatically. Otherwise, you will have to cycle through the colours yourself, but that is not difficult.