Plot two looping variables

Question

Tomas White 2022-5-2

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1710295-plot-two-looping-variables

评论： Voss 2022-5-3

Hello! I have this code which generates multiple values of the variable "CL" by iterating the variable "aoa", my problem is that when I try to plot both variables I generate a graph per "aoa" iteration and not all iterations in a single graph. I tried various methods and code combinations but nothing seems to do the job. Any help is much aprreciated!

%LLT
fprintf('Lifting line theory - 7.1 \n')
%Inputs
fprintf('------------------------------------------------------------- \n')
zeroliftd=-1.2;
aoainitiald=4;
aoafinald=10;
AR=9;
fprintf('------------------------------------------------------------- \n')
%input adjustments (deg to rad)
aoainitial=((aoainitiald*pi)/180);
aoafinal=((aoafinald*pi)/180);
zerolift=((zeroliftd*pi)/180);
%Station phi values
station=[1,2,3,4]';
s1phi=22.5;
s2phi=45;
s3phi=67.5;
s4phi=90;
phin=[s1phi,s2phi,s3phi,s4phi];
phi=phin.';
%Calculus - table 7.1
cosphi=cosd(phi);
sinphi1=sind(phi);
sinphi3=sind(3*phi);
sinphi5=sind(5*phi);
sinphi7=sind(7*phi);
miu=0.24933*(1-0.6*cosd(phi));
aoa=aoainitial;
while ((aoa) <= (aoafinal))
    %table 7.1 display
    fprintf('------------------------------------------------------------- \n')
    fprintf('------------------------------------------------------------- \n')
    fprintf('Math process corresponding to angle of attack (degrees) =')
    dispaoa=aoa*(180/pi);
    disp(dispaoa)
    
    matrix1=[station,phi,cosphi,sinphi1,sinphi3,sinphi5,sinphi7,miu];
    fprintf('Table 7.1: \n')
    disp(matrix1);
    fprintf('------------------------------------------------------------- \n')
    %equation 7.31
    %equation second member
    L1=((matrix1(1,8))*(aoa-zerolift)*(matrix1(1,4)));
    L2=((matrix1(2,8))*(aoa-zerolift)*(matrix1(2,4)));
    L3=((matrix1(3,8))*(aoa-zerolift)*(matrix1(3,4)));
    L4=((matrix1(4,8))*(aoa-zerolift)*(matrix1(4,4)));
    Ltotaln=[L1,L2,L3,L4];
    Ltotal=Ltotaln';
    fprintf('Second member matrix for equation system 7.31: \n')
    disp(Ltotal);
    fprintf('------------------------------------------------------------- \n')
    %matrix: A1
    ma11=(matrix1(1,4))*((matrix1(1,8))+(matrix1(1,4)));
    ma13=(matrix1(2,4))*((matrix1(2,8))+(matrix1(2,4)));
    ma15=(matrix1(3,4))*((matrix1(3,8))+(matrix1(3,4)));
    ma17=(matrix1(4,4))*((matrix1(4,8))+(matrix1(4,4)));
    ma1n=[ma11,ma13,ma15,ma17];
    ma1=ma1n';
    %matrix: A3
    ma31=(matrix1(1,5))*(3*(matrix1(1,8))+(matrix1(1,4)));
    ma33=(matrix1(2,5))*(3*(matrix1(2,8))+(matrix1(2,4)));
    ma35=(matrix1(3,5))*(3*(matrix1(3,8))+(matrix1(3,4)));
    ma37=(matrix1(4,5))*(3*(matrix1(4,8))+(matrix1(4,4)));
    ma3n=[ma31,ma33,ma35,ma37];
    ma3=ma3n';
    %matrix: A5
    ma51=(matrix1(1,6))*(5*(matrix1(1,8))+(matrix1(1,4)));
    ma53=(matrix1(2,6))*(5*(matrix1(2,8))+(matrix1(2,4)));
    ma55=(matrix1(3,6))*(5*(matrix1(3,8))+(matrix1(3,4)));
    ma57=(matrix1(4,6))*(5*(matrix1(4,8))+(matrix1(4,4)));
    ma5n=[ma51,ma53,ma55,ma57];
    ma5=ma5n';
    %matrix: A7
    ma71=(matrix1(1,7))*(7*(matrix1(1,8))+(matrix1(1,4)));
    ma73=(matrix1(2,7))*(7*(matrix1(2,8))+(matrix1(2,4)));
    ma75=(matrix1(3,7))*(7*(matrix1(3,8))+(matrix1(3,4)));
    ma77=(matrix1(4,7))*(7*(matrix1(4,8))+(matrix1(4,4)));
    ma7n=[ma71,ma73,ma75,ma77];
    ma7=ma7n';
    %matrix system
    %equation first member
    equationmatrix1=[ma1,ma3,ma5,ma7];
    fprintf('First member matrix for equation system 7.31: \n')
    disp(equationmatrix1);
    fprintf('------------------------------------------------------------- \n')
    %equation system solver
    matrixA=linsolve(equationmatrix1,Ltotal);
    %An matrix
    fprintf('Equation system 7.31 solution: \n')
    fprintf('A1 = ')
    disp(matrixA(1,1));
    fprintf('A3 = ')
    disp(matrixA(2,1));
    fprintf('A5 = ')
    disp(matrixA(3,1));
    fprintf('A7 = ')
    disp(matrixA(4,1));
    fprintf('------------------------------------------------------------- \n')
    %Lift coefficient for inputed angle of attack:
    fprintf('Corresponding CL for inputed angle of attack:\n')
    CLin=(matrixA(1,1))*3.14159*AR;
    fprintf('CL:');
    disp(CLin);
    fprintf('------------------------------------------------------------- \n')
    %Theoretical value of induced drag coefficient for inputed angle of attack:
    fprintf('Corresponding induced theorical CD for inputed angle of attack:\n')
    CDin=(((CLin)^2)/(3.14159*AR))*(1+((3*(matrixA(2,1))^2)/((matrixA(1,1))^2))+((5*(matrixA(3,1))^2)/((matrixA(1,1))^2))+((7*(matrixA(4,1))^2)/((matrixA(1,1))^2)));
    fprintf('Cd:');
    disp(CDin);
    
    aoa=aoa+pi/180;
end
plot(aoa,CLin);

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Answer 1

Voss 2022-5-2

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1710295-plot-two-looping-variables#answer_955880

在 MATLAB Online 中打开

In order to see how aoa and CLin change in each iteration of the while loop, you can either: (1) plot them each time through the loop, or (2) collect all their values in arrays and plot the arrays after the loop.

Method 1 would have this kind of structure:

aoa=aoainitial;
while aoa < aoafinal
    
    % ...
    % calculate CLin
    % ...
    
    plot(aoa,CLin,'o'); % 'o' is a data marker, which is necessary to see a line with only one point
    hold on % use hold on to keep each plotted line (in this case each plotted point)
    
    aoa=aoa+pi/180;
    
end

Method 2 would have this kind of structure:

aoa_array = [];
CLin_array = [];
aoa=aoainitial;
while aoa < aoafinal
    
    % ...
    % calculate CLin
    % ...
    
    aoa_array(end+1) = aoa; % add the new values to the end of the arrays
    CLin_array(end+1) = CLin;
    
    aoa=aoa+pi/180;
    
end
plot(aoa_array,CLin_array); % plot the arrays