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fprintf %f

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Zach
Zach 2011-10-1
I have an fprintf command
fprintf('\n %s \n%0.3f',Data{:})
where my data contains a sentence and then an array. I want the decimal places for the array to only go to 3 which seems only work for every other number. So every thing comes out fine but it looks like this:
Sentence
1.784
2.862691e+000
2.737
2.855501e+000
2.976
i dont want the exponentials
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Jan
Jan 2011-10-1
Please post the contents of the Data cell. I cannot imagine, that the posted format string can create the shown answer.

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采纳的回答

Image Analyst
Image Analyst 2011-10-1
Your format specifier string expects Data to have the form "string number string number string number etc." Apparently Data{1} is a string but I'm not sure Data{3} and Data{5} are. They're probably numbers, not strings, so when it tries to print those numbers out as strings (according to %s) you get the unexpected results. Show us how you constructed Data.
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Zach
Zach 2011-10-1
Data={'The calculated means for ERP0 are ','The standard deviations for ERP0 are ', 'The calculated means for ERP08 ', 'The standard deviations for ERP08 are ';[1,2,3] [4,5,6] [7,8,9] [10,11,12]};
fprintf('\n %s \n%0.3f',Data{:})
Image Analyst
Image Analyst 2011-10-1
You have 3 numbers for each string, so you need to do
fprintf('\n %s \n%0.3f %.3f %.3f',Data{:})

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更多回答（1 个）

Jan
Jan 2011-10-1
I guess that your Data are:
Data = {'Sentence', [1.784, 2.862691, 2.737, 2.855501, 2.976]};
When you use the format string '\n %s \n%0.3f' every second number is displayed using the '%s' format. So you have to split the string from the numerical data:
fprintf('\n %s', Data{1});
fprintf(' \n%0.3f', Data{2});
Or perhaps: fprintf(' \n%0.3f', Data{2:end});

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