convert cell to an integrable function

1 次查看(过去 30 天)
Dear all,
I want to enter several functions as function handles as input to a function and integrate them according the the prescribed variable in handle, a schematic representation of my request is as follow:
function y=ftest(func)
for i=1:size(func,2)
f=func;
ff=f{i};
y(i)=integral(@(var) ff(var),0,1);
end
end
Any help would be greatly appreciated :)
  2 个评论
Jan
Jan 2022-5-27
Yes, this looks good. I'd omit the indirection over f and use func directly. And if func contains a cell of function handles already, there is no need to convert them to a function handle:
function y=ftest(func)
y = zeros(1, size(func, 2)); % Pre-allocate
for i = 1:size(func,2)
ff = func{i};
y(i) = integral(ff, 0, 1); % Or directly: integral(func{i}, 0, 1);
end
end
Do you have problems with your code? What exactly do you use as input? Do you get an error message? If so, which one?

请先登录,再进行评论。

回答(1 个)

Joel Van Sickel
Joel Van Sickel 2022-6-10
This question was answered by Jan in the comments. To clean up the answers section, I am posting it down here as well:
Yes, this looks good. I'd omit the indirection over f and use func directly. And if func contains a cell of function handles already, there is no need to convert them to a function handle:
ThemeCopy
function y=ftest(func)
y = zeros(1, size(func, 2)); % Pre-allocate
for i = 1:size(func,2)
ff = func{i};
y(i) = integral(ff, 0, 1); % Or directly: integral(func{i}, 0, 1);
end
end
Do you have problems with your code? What exactly do you use as input? Do you get an error message? If so, which one?

类别

Help CenterFile Exchange 中查找有关 Scripts 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by