Crack Detection Annotation Issue

Question

文辉沈 2022-6-2

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1732110-crack-detection-annotation-issue

编辑： Chunru 2022-6-3

在 MATLAB Online 中打开

How do I label it after the crack size is calculated?

I am currently using text()

1、The length of the crack I marked at the midpoint of the line segment

plot([coord1(1), coord2(1)],[coord1(2), coord2(2)],'b','LineWidth',2);
text((coord1(1)+coord2(1))/2,(coord1(2)+coord2(2))/2,[' ','Length = ',num2str(length)],'Color','b');

2、I just mark the angle in the upper left corner, is there any function that can draw the angle arc, and then mark the angle next to the angle arc

text(20,20,['Angle = ',num2str(angle),'°'],'Color','b');

3、Width, I can only know which line to take the maximum value, but I can't return the coordinates of the two ends where the maximum value is located. Is there any solution?

for i = 1:c
    width = find(bw(i,:),1,'last')-find(bw(i,:),1,'first');
    K(i)=width;
end
Width = max(K);

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文辉沈 2022-6-2

When the length is marked, the characters exceed the image frame when saving, how to solve this?

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Answer 1

Chunru 2022-6-2

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1732110-crack-detection-annotation-issue#answer_976485

编辑：Chunru 2022-6-3

在 MATLAB Online 中打开

1、The length of the crack I marked at the midpoint of the line segment: Use horizontal alignment

plot([coord1(1), coord2(1)],[coord1(2), coord2(2)],'b','LineWidth',2);
text((coord1(1)+coord2(1))/2,(coord1(2)+coord2(2))/2,[' ','Length = ',num2str(length)],'Color','b', ...
    'HorizontalAlignment','center');   % center or right

2、I just mark the angle in the upper left corner, is there any function that can draw the angle arc, and then mark the angle next to the angle arc

text(20,20,['Angle = ',num2str(angle),'°'],'Color','b');
% Assume (x0, y0) be the coordinates or the angle vertex
theta = linspace(0, angle, 50);
r = 10;     % radius of the arc
plot(x0+r*sind(theta), y0+r*cosd(theta), 'b-');

3、Width, I can only know which line to take the maximum value, but I can't return the coordinates of the two ends where the maximum value is located. Is there any solution?

maxw = 0;           % max width
for i = 1:c
    wr = find(bw(i,:),1,'last');
    wl = find(bw(i,:),1,'first')
    width = wr-wl;
    if width > maxw
        maxw = width;
        maxwl = wl;
        maxwr = wr;
    end
    %K(i)=width;
end
maxw, maxwl, maxwr