Loop with 2 diferent iterations conuntings

Question

jose Hlunguane 2022-6-6

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编辑： Jan 2022-7-8

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I intend to make a loop that performs two counts in parallel:

1) i, must count the total number of iterations;

2) ii, must count only the iterations under the condition: H[D(t)] <= 0; {H[D(t)] = Delta - E[D(t)]}

I'm having trouble matching/synchronizing the iterations.

iterations = i + n; %
%Calculation of accumulated fatigue damage
for i = 1:iterations    
    .
    .
    . 
    %accumulated fatigue damage estimate
    D_t = dLTi.*operationtime;
    fprintf('result %i\n', D_t);
end
ii = ii + 1;
%performance function evaluation
for ii = 1:iterations
    expecteddamage = (D_t + D_E)./i;
    %Limit State Function evaluation
    limitsfunction = Delta - expecteddamage;
    fprintf('result %d\n', limitsfunction);
    %failure condition checking    
    if limitsfunction <= 0
        fprintf('system failed %Delta is smaller than.\n', expecteddamage);     
    end

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Jan 2022-6-6

Please do not invent your own notation and expect, that others can guess, what is meant.

What does this mean: H[D(t)] <= 0; {H[D(t)] = Delta - E[D(t)]}

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Answer 1

Voss 2022-6-28

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total_count = 0;
conditional_count = 0;
max_iter = 10000;
for iter = 1:max_iter
    
    total_count = total_count + 1;
    
    if isprime(iter)
        conditional_count = conditional_count + 1;
    end
    
end
disp(total_count);
       10000
disp(conditional_count);
        1229

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Answer 2

jose Hlunguane 2022-7-7

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Ooh Jan, sorry though!

H[D(t)] - stand for limit state function dependent on D(t) accumulated fatigue damage;

Delta - is the system material resistence: Delta = 1;

E[D(t)] - is the expected fatigue damage

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Jan 2022-7-8

编辑：Jan 2022-7-8

Again: While the physical meaning of the values does not matter, the notation "H[D(t)]" is not defined. In Matlab [ ] is the concatenation operator for arrays. Of course you know, what the square brackets and curly braces should mean in your question, but the readers cannot guess this.

Prefer the standard Matlab syntax, because you can expect it to be known in a Matlab forum.

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