the function can only take one input argument

Question

Nawaf Aldhawi 2022-6-8

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1736340-the-function-can-only-take-one-input-argument

编辑： Jan 2022-6-8

so when i a make a function called analyzeT to analyze temperatures i can't enter the temp's this way "analyzeT(28,44,50,33)' it tells me that there's too many input arguments but when i make a vector first and store the values in it then i write 'analyzeT(vector)' it works, anyway i can make the first way work? thanks!

this is the function

function [maxT,minT,avgT] = analyzeT(temp)
i = length(temp);
maxT = temp(2);
minT = temp(1);
sum = 0;
for i = 1:i
    if temp(i) > maxT
        maxT = temp(i);
    elseif temp(i) < temp(1)
        minT = temp(i);
    else
    end
    sum = temp(i) + sum;
end
avgT = sum/length(temp);
end

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Jan 2022-6-8

编辑：Jan 2022-6-8

在 MATLAB Online 中打开

Why do you assume, that maxT cannot be temp(1) ?

This is not a but, but very ugly:

i = length(temp);
for i = 1:i

If maxT and minT are set to temp(1), you do not have to check temp(1) again.

Together:

nTemp   = length(temp);
maxT    = temp(1);
minT    = temp(1);
sumTemp = temp(1);
for i = 2:nTemp
    ...
end

Avoid using the names of builtin functions as variables. This is not an error, but a frequent source of unexpected behavior if you use the function sum() later.

I do not think, that this is exactly what you want:

elseif temp(i) < temp(1)
    minT = temp(i);
else  % Omit this orphaned else, if it is not used.
end

Do you really want to compare the temperatures with temp(1), or with minT?

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Answer 1

Jan 2022-6-8

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1736340-the-function-can-only-take-one-input-argument#answer_981410

编辑：Jan 2022-6-8

在 MATLAB Online 中打开

Either modify the call to create the vector dynamically:

analyzeT([28,44,50,33])
%        ^           ^

Or create a new input interface for the function (which is not efficient or nice in this example):

function [maxT,minT,avgT] = analyzeT(varargin)
if nargin == 1
    temp = varargin{1};
else
    remp = [varargin{:}];  % Concatenate inputs to a vector
end
...