Why am I getting syntax

2022 6 13
1 个回答
更新时间：2022 6 13
11 次查看（30 天）

0 个投票

dwdx=@(X)ks*(((FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))-(((FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X))*((FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))/(Ke)))/(((1+(KA.*(FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))+(KB.*(FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X)))+(KC.*(FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))).^2);
I dont know where i go wrong. I keep on getting syntax parentheses error.

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回答（1 个）

Benjamin Thompson
Benjamin Thompson 2022-6-13

0 个投票

Missing two closing parenthesis it would appear. Is MATLAB suggestion not correct? You might do better breaking this up into multiple lines using the ... operator notation for easier readability.
>> dwdx=@(X)ks*(((FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))-(((FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X))*((FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))/(Ke)))/(((1+(KA.*(FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))+(KB.*(FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X)))+(KC.*(FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))).^2);
dwdx=@(X)ks*(((FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))-(((FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X))*((FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))/(Ke)))/(((1+(KA.*(FA0.*(1-X).*R.*T.*y)./(v.*(1+esp.*X)))+(KB.*(FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+esp.*X)))+(KC.*(FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+esp.*X)))).^2);
↑
Invalid expression. When calling a function or indexing a variable, use parentheses. Otherwise, check for mismatched delimiters.
Did you mean:
>> dwdx=@(X)ks*(((FA0.*(1-X).*R.*T.*y)./(v.*(1+eps.*X)))-(((FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+eps.*X))*((FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+eps.*X)))/(Ke)))/(((1+(KA.*(FA0.*(1-X).*R.*T.*y)./(v.*(1+eps.*X)))+(db.*(FA0.*(theta_B+X).*R.*T.*y)/(v.*(1+eps.*X)))+(KC.*(FA0.*(theta_C+X).*R.*T.*y)/(v.*(1+eps.*X)))).^2)));

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