How to find vector with if loops and for loops

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Ömer Durkut
Ömer Durkut 2022-6-15
编辑： Torsten 2022-6-24
Given a vector u with the dimension 20x1, which consists of random variables from a uniform distribution (distributed on [0,1]) exists. Instructions: • Create a code in MATLAB, – which creates the vector u, – which contains both ’for loops’ and ’if loops’, – and for all values in the vector u indicates in which quarter the number lies.This is one of my mathlab final exam question, could you please help me,i just know that i should use "rand" function
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Torsten
Torsten 2022-6-15
Ok, then - under the link given - you get the hints the forum is willing to give to solve this assignment.

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Image Analyst
Image Analyst 2022-6-16
Are you allowed to turn in other people's solutions as your own for your final exam question?
The first 5 values of the 20-element u lie in the first quarter, the next 5 in the second quarter, the third 5 in the third quarter, and the final 5 elements in indexes 16-20 obviously lie in the last quarter. But I think they want you to use a for loop
u = rand( % You said you got this
for k = 1 : length(u)
if u(k)...........
More code
end
end
You can either store the quarter that the number lives in, in a vector called quarter, or maybe you just want to print out the quarter it's in using fprintf(). Or maybe you want to do both.
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Image Analyst
Image Analyst 2022-6-24
@Jan, true. I just basically took the OP's code but an experienced programmer would do it more like this:
n = 20;
r = rand(n,1);
for k = 1 : numel(r)
if r(k) < 0.25
quarter(k) = 1;
elseif r(k) < 0.50
quarter(k) = 2;
elseif r(k) < 0.75
quarter(k) = 3;
else % r(k) >= 0.75
quarter(k) = 4;
end
end
quarter
Torsten
Torsten 2022-6-24
编辑：Torsten 2022-6-24
I like if the order of the conditions in if-statements can be changed.
This is not the case in this simplified version because
if r(k) < 0.75
quarter(k) = 3;
elseif r(k) < 0.25
quarter(k) = 1;
elseif r(k) < 0.5
quarter(k) = 2;
else
quarter(k) = 4;
end
would create chaos.

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