Average of every 25 rows in a table

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Hello,
I have a table of 10 columns and 1000 rows. I would like to take the average of each column for every 25 rows. How to code that please?
Thank you

采纳的回答

Abhishek Tiwari
Abhishek Tiwari 2022-7-3
Hi,
This might work,
% Sample data
data = rand(1000, 10);
% Calculating Output Dimension (#columns will be same)
rows = 1000/25;
output = ones(rows, 10);
% Start first 25 entries then compute mean and increase index for next
% 25 entries
for row = 0:rows-1
output(row+1, :) = mean(data(25*row+1:25*(row+1),:));
end
output
output = 40×10
0.5329 0.5851 0.5010 0.5203 0.4864 0.3876 0.5029 0.5378 0.4667 0.4931 0.5315 0.5217 0.5169 0.5313 0.5383 0.4457 0.4606 0.5541 0.4590 0.6092 0.4712 0.4571 0.4326 0.4300 0.5599 0.5561 0.5522 0.5662 0.5468 0.5205 0.4788 0.4865 0.4554 0.4486 0.5526 0.5052 0.3405 0.5116 0.5173 0.5189 0.4536 0.3814 0.5256 0.4594 0.4725 0.5219 0.5299 0.4808 0.4840 0.5354 0.3794 0.3971 0.4839 0.5850 0.3706 0.5975 0.6139 0.5391 0.3941 0.5435 0.5360 0.5580 0.5243 0.5750 0.4471 0.4273 0.5424 0.4981 0.4707 0.4634 0.4814 0.4900 0.6158 0.4795 0.4305 0.4495 0.4998 0.5014 0.4877 0.4645 0.4974 0.4583 0.4654 0.6242 0.4960 0.5045 0.4318 0.4466 0.3654 0.5716 0.4906 0.4275 0.3932 0.5329 0.5218 0.5332 0.4855 0.4368 0.3938 0.4639
  3 个评论
Abhishek Tiwari
Abhishek Tiwari 2022-7-5
编辑:Abhishek Tiwari 2022-7-5
Just defining dimension of output table... It is better than create one dynamically, saves time. When we average every 25 rows for each column dimension of output table is reduced from 1000 to 1000/25 (=40) but column remains same.
Reem RA
Reem RA 2022-7-5
Thank you, I tried it and it worked.

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更多回答(1 个)

Akira Agata
Akira Agata 2022-7-3
编辑:Akira Agata 2022-7-3
Another possible solution:
% Sample data
data = rand(1000, 10);
% Grouping
group = repelem(1:size(data, 1)/25, 25)';
% Apply mean function for each group
output = splitapply(@mean, data, group);
  3 个评论
Akira Agata
Akira Agata 2022-7-4
Hi @Rulla RA-san,
I just wanted to create "group number".
For more information, please take a look at the following.
Reem RA
Reem RA 2022-7-5
Thanks a lot, this worked well too!!!

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