couldn't understand what's wrong in the function definition.

Question

SAHIL SAHOO 2022-7-19

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1763340-couldn-t-understand-what-s-wrong-in-the-function-definition

回答： Walter Roberson 2022-7-19

采纳的回答： Walter Roberson

f = @(t,y) [

((y(2)-a-l.*(abs(cos(y(3)+ pi/4)))).*y(1) + k.*y(1).*cos(y(3)- pi/2)).*(2/tc);

(P - (y(2).*(y(1) + 1))) / tf;

o - (k./tc).*2.* sin(y(3)));

];

getting a problem

"Invalid expression. When calling a function or indexing a variable, use parentheses. Otherwise, check for

mismatched delimiters." in this.

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Answer 1

Walter Roberson 2022-7-19

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https://ww2.mathworks.cn/matlabcentral/answers/1763340-couldn-t-understand-what-s-wrong-in-the-function-definition#answer_1010555

在 MATLAB Online 中打开

    o - (k./tc).*2.* sin(y(3)));
        1     0         1 2 10!

the digits are the nesting level "after" the character above. You open and then close brackets, leaving zero open brackets. You then open two brackets... and you close three brackets, one more than you opened.

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Answer 2

Chunru 2022-7-19

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1763340-couldn-t-understand-what-s-wrong-in-the-function-definition#answer_1010550

在 MATLAB Online 中打开

a =1; P=2; i=3; tf=4; k=5; l=6; tc=7; o=8;
f = @(t,y) [  ( (y(2)-a-l.*(abs(cos(y(3)+ pi/4)) )).*y(1) + k.*y(1).*cos(y(3)- pi/2)).*(2/tc);
               (P - (y(2).*(y(1) + 1))) / tf;
                o - (k./tc).*2.* sin(y(3)) ]      
f = function_handle with value:
    @(t,y)[((y(2)-a-l.*(abs(cos(y(3)+pi/4)))).*y(1)+k.*y(1).*cos(y(3)-pi/2)).*(2/tc);(P-(y(2).*(y(1)+1)))/tf;o-(k./tc).*2.*sin(y(3))]
f(1, [1; 2; 2])
ans = 3×1
   -0.0220
   -0.5000
    6.7010