A compact way to remove empty rows in a cell array matrix ?
显示 更早的评论
A compact way to remove empty rows in a cell array matrix, as the following one?
>> a
a =
8×2 cell array
{'22-Jul-2021 17:00:00'} {[ 49]}
{0×0 double } {0×0 double}
{0×0 double } {0×0 double}
{0×0 double } {0×0 double}
{0×0 double } {0×0 double}
{'27-Jul-2021 20:00:00'} {[ 123]}
{'28-Jul-2021 06:00:00'} {[ 21]}
{'29-Jul-2021 13:00:00'} {[ 66]}
I tried this solution, but is there any more compact way ?
i = cellfun(@isempty,a);
a( any(i,2), : ) = []
a =
4×2 cell array
{'22-Jul-2021 17:00:00'} {[ 49]}
{'27-Jul-2021 20:00:00'} {[123]}
{'28-Jul-2021 06:00:00'} {[ 21]}
{'29-Jul-2021 13:00:00'} {[ 66]}
4 个评论
That is probably about the best you can do.
In case anyone wants to experiment,
a = {
'22-Jul-2021 17:00:00', 49
[], []
[], []
[], []
[], []
'27-Jul-2021 20:00:00', 123
'28-Jul-2021 06:00:00', 21
'29-Jul-2021 13:00:00', 66 }
Sim
2022-8-11
Jan
2022-8-11
As long, as the cell does not contain strings (char vectors are okay), cellfun('isempty', a) is faster than using @isempty.
Sim
2022-8-11
采纳的回答
a = {
'22-Jul-2021 17:00:00', 49
'', []
'', []
'', []
'', []
'27-Jul-2021 20:00:00', 123
'28-Jul-2021 06:00:00', 21
'29-Jul-2021 13:00:00', 66 }
a= table2cell(rmmissing(cell2table(a)))
更多回答（0 个）
类别
在 帮助中心 和 File Exchange 中查找有关 Characters and Strings 的更多信息
Translated by 
