Letter to numerb: Create a new 'if' variable to change 'Y' and 'N' to 1 and 0
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I would like to create a new variable and change those 'N's and 'Y's to 0 (N) and 1 (Y).
Does someone know an easy way to solve the problem?
Best regards
Max
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dpb
2022-8-14
>> categorical({'Y';'N';'Y'},{'N';'Y'},{'0';'1'})
ans =
3×1 categorical array
1
0
1
>> matches({'Y';'N';'Y'},'Y')
ans =
3×1 logical array
1
0
1
>> categorical(matches({'Y';'N';'Y'},'Y'))
ans =
3×1 categorical array
true
false
true
>>
2 个评论
dpb
2022-8-14
编辑:dpb
2022-8-14
What does that mean, pray tell? What is "it" and what are you trying to accomplish?
Above is three slightly different approaches to converting a string variable Y/N to a logical one...
BTW, there's no data in the attached spreadsheet that shows anything that appears to be at all related to the question asked...
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