Problem with reaching specific values of an array or matrix

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Go Sugar 2022-8-15

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1779560-problem-with-reaching-specific-values-of-an-array-or-matrix

编辑： Go Sugar 2022-8-15

Hello. I have a for loop, for each value of counter, I want to find the relevent raw value when rs==1 or ep==1 from various excel files.

If rs==1, I want it to write t_c's relevant value corresponding its raw value.

If ep==1, I want it to write t_c's relevant value corresponding its raw value + 1.

However, when I consider raw value + 1, I get zero values (even without if loop). I do not understand why this happens so? When I try to find its relevant value for raw value, I get true values (without the if loop). I would be happy if I solved this question.Thank you. :)

Below is a part of my code:

ep=mydata(:,1);
counter=mydata(:,2);
rs=mydata(:,3);
t_c=mydata(:,4);
t=[]; 
raw=[];
for n=0:4
    f=1;
    raw(f)=find((counter == n)  & ((rs==1) | (ep==1)))
    y(f)=raw(f)+1
    
    if (rs==1)
        te(f)=t_c(raw(f))
    else (ep==1)
        te(f)=t_c(y(f))       
    end
    
    t=[t te(f)]
    C=table(t);  
    f=f+1;
end

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dpb 2022-8-15

I'd suggest posting your final code as an Answer, then -- you can Accept your own. Serves to let folks know the problem is sovled if nothing else.

Go Sugar 2022-8-15

Ok, I have just posted it. Thank you so much for the quick replies. :)

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采纳的回答

Go Sugar 2022-8-15

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/1779560-problem-with-reaching-specific-values-of-an-array-or-matrix#answer_1027020

编辑：Go Sugar 2022-8-15

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This is the finalized version of the code. It is working as expected. Thank you for all the help. :)

ep=mydata(:,1);
counter=mydata(:,2);
rs=mydata(:,3);
t_c=mydata(:,4);
a=mydata(:,5);
t=[]; 
raw=[];
for n=0:4
    f=1;
    raw(f)=find((counter == n)  & ((rs==1) | (ep==1)));
    y(f)=raw(f)+1;
    
    if (a==0)
        te(f)=t_c(raw(f));
    else 
        te(f)=0;      
    end
    
    t=[t te(f)]
    C=table(t);  
    f=f+1;
end